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aliina [53]
2 years ago
14

Samantha opened a savings account and deposited $8192. The account earns 10% in interest annually. She makes no further deposits

and does not withdraw any money. In t years, she has $25,710 in this account. Write an equation in terms of t that models the situation.
Mathematics
2 answers:
Leokris [45]2 years ago
4 0
The formula for this is A=P(1+r/n)^nt
Where A is the total amount. P is the principal amount. 1 represent 100%. R is the rate. N is the number for annual, quarter, or etc. T is the time given in the question. If you put the numbers that is given in the question and put it in the formula, you will have:
$25,710 = $8192(1 + 0.10/12)^12t
3.14= (1.00833333)^12t
12t= log1.00833333 3.14
t= (log1.00833333 3.14)/12
t is approximately 11.5 yrs
Usimov [2.4K]2 years ago
3 0

Answer: 8192⋅(1.10)t

Step-by-step explanation:

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What is the length of segment BD? Round your answer to the nearest hundredth. triangles ABC and ABD in which the triangles share
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Answer:

BD = 4.99 units

Step-by-step explanation:

Consider the triangle ABD only.

The angle formed is 31 degrees which occurs between two sides that are AD and BC.

We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base.

Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD

Using formula for tanθ

tanθ = Perpendicular/Base

tan31 = 3/BD

0.601 = 3/BD

BD = 3/0.601

BD = 4.99 units

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A parabola is represented by the equation y = x2 + 6x − 17. The x-intercepts of the parabola are____ and_____ . The y-intercept
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2.8, 8.8, and -17 respectively.

Step-by-step explanation:

We need to find roots of the equation.

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If g (x) = StartFraction x + 1 Over x minus 2 EndFraction and h(x) = 4 – x, what is the value of (g circle h) (negative 3)? Eigh
brilliants [131]

Answer:

Step-by-step explanation:

Given  g (x) = \frac{x+1}{x-2} and h(x) = 4-x, we are to find (goh)(-3)

First we need to get (goh)(x)

(goh)(x) = g(h(x))\\g(h(x))= g(4-x)\\g(4-x) = \frac{(4-x)+1}{(4-x)-2}\\ g(4-x) =  \frac{5-x}{2-x}\\substitute \ x = -3 \ into \ resulting \ function\\ g(4-x) =  \frac{5-x}{2-x}\\(goh)(-3) =  \frac{5-(-3)}{2-(-3)}\\\\(goh)(-3) =  \frac{8}{5}\\

Hence (goh)(x)\ is \ Eight-fifths

Also given f(x) = x and g(x) = 1/x, we are to find (fog)(x)

(fog)(x) = f(g(x))\\f(g(x)) = f(\frac{1}{x}  )\\ since \ f(x) = x^2, we\ will \ repalce\ x \ with \ \frac{1}{x} \ to \ have;\\ f(\frac{1}{x}  ) =( \frac{1}{x})^2\\\\

f(\frac{1}{x} ) = \frac{1}{x^2}

For the pair of function f(x) = 2/x and g(x) = 2/x

f(g(x)) = f(2/x)

f(2/x) = 2/(2/x)

f(2/x) = 2*x/2

f(2/x) = x

Hence f(g(x)) = x

For the pair of function f(x) = x-2/3 and g(x) = 2-3x

f(g(x)) = f(2-3x)

f(2-3x) = (2-3x-2)/3

f(2-3x) = -3x/3

f(2-3x) = -x

f(g(x)) = -x for the pair of function

For the pair of function f(x) = x/2 - 2 and g(x) = x/2 + 2

f(g(x)) = f(x/2 + 2)

f(x/2 + 2) = f((x+4)/2)

f((x+4)/2) =  [(x+4)/2]/2 - 2

f((x+4)/2) =  (x+4)/4 - 2

find the LCM

f((x+4)/2) =  [(x+4)-8]/4

f((x+4)/2) =  (x-4)/4

Hence f(g(x)) for the pair of function is (x-4)/4

8 0
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