Mr robbins earns a commission on each airfare he books. At the end of the day,he had booked $208.60 worth if airfare and earned
1 answer:
Answer:
Mr. Robins commision rate is 15%.
Step-by-step explanation:
Formula
As given
Mr robbins earns a commission on each airfare he books.
At the end of the day,he had booked $208.60 worth if airfare and earned $31.29.
Here
Part value = $31.29
Total value = $208.60
Put in the formula
Percentage = 15%
Therefore the Mr. Robins commision rate is 15%.
You might be interested in
Answer:
First option:
Step-by-step explanation:
Given the quadratic equation , you need to factor it.
To do this, you need to find two number that when you add them you get 11 and when you multply them you get 24. These numbers are: 8 and 3.
Therefore, knowing this, you can factor the quadratic equation:
Then, is equivalent to the graph of the equation
, which matches with the first option.
Answer:
The product results in: , which agrees with answer A of the given choices.
Step-by-step explanation:
We need to apply distributive property for the product of two expressions each consisting of two terms, and also use the properties of products of radicals of the same root:
and now, we extract as many factors we can from the roots to reduce them:
Answer:
15.43 ft
Step-by-step explanation:
To solve this question, one should use the concept of similar triangles.
The pole's shadow and the distance to the ground (x) form a similar triangle to the distance of the plumb bob from the base and the length of the plumb bob, respectively. Note that we do not need to know the measurements of the third side of the triangles to solve the problem. Therefore, the distance of the top of the pole to the ground is:
The distance of the top of the pole to the ground is 15.43 ft.
Answer:
95% of the text messages have length between 23 units and 47 units.
Step-by-step explanation:
We are given the following in the question:
The lengths of text messages are normally distributed.
95% confidence interval:
(23,47)
Thus, we could interpret the confidence interval as:
About 95% of the text messages have length between 23 units and 47 units.
By Empirical rule for a normally distributed data, about 95% of data lies within 2 standard deviations of mean , thus we can write:
Thus, the mean length of text messages is 23 units and standard deviation is 6 units.