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2 years ago

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Tracy had a total of $200 to spend while shopping. She has already spent $134 on clothes. She wants to buy some video games that

are on sale for $20 each, including tax. Enter the maximum number od video games Tracy can buy with the remaining money.

1 answer:

Alisiya [41]2 years ago

5 0

Answer:

She can buy a total of <u>3 games</u> with the left over money.

Step-by-step explanation:

200 - 134 = 66

66/20 = 3

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Answer:

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Step-by-step explanation:

Let A = player A wins,

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2 years ago

You put $1200 in an account that earns 3% simple interest. Y= a (1 + r)t Find the total amount in the account after four years.

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Hello!

To find how much money total will be in the account after four years, you need to use the function, $y = a(1 + r)^{t}$ , as seen above. In this function, a is the starting value, r is the interest rate, and t is the amount of time (in years).

Before substituting values into the function, we need to convert 3% into a decimal. Remember that all percentages are out of 100, so we divide 3 by 100 and remove the percentage sign, or move the decimal two places to the left.

3/100 = 0.03 | 0.03 is the interest rate.

With all the necessary values, we can find the total amount in the account. In this case, a = 1200, r = 0.03, and t = 4.

$y = 1200(1 + 0.03)^{4}$

$y = 1200(1.03)^{4}$

$y = 1200(1.12550881)$

y = 1350.610572, which can be rounded to 1350.61 dollars.

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2 years ago

Mr. Scott uses an 8 GB flash drive to store his files for his classroom. His principal buys him a new 64 GB flash drive. What is

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Step-by-step explanation:

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2 years ago

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Which of the following are dimensionally consistent? (Choose all that apply.)(a) a=v / t+xv2 / 2(b) x=3vt(c) xa2=x2v / t4(d) x=v

Bumek [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

A

is dimensionally consistent

B

is not dimensionally consistent

C

is dimensionally consistent

D

is not dimensionally consistent

E

is not dimensionally consistent

F

is dimensionally consistent

G

is dimensionally consistent

H

is not dimensionally consistent

Step-by-step explanation:

From the question we are told that

The equation are

$A) \ \ a^3 = \frac{x^2 v}{t^5}$

$B) \ \ x = t$

$C \ \ \ v = \frac{x^2}{at^3}$

$D \ \ \ xa^2 = \frac{x^2v}{t^4}$

$E \ \ \ x = vt+ \frac{vt^2}{2}$

$F \ \ \ x = 3vt$

$G \ \ \ v = 5at$

$H \ \ \ a = \frac{v}{t} + \frac{xv^2}{2}$

Generally in dimension

x - length is represented as L

t - time is represented as T

m = mass is represented as M

Considering A

$a^3 = (\frac{L}{T^2} )^3 = L^3\cdot T^{-6}$

and $\frac{x^2v}{t^5 } = \frac{L^2 L T^{-1}}{T^5} = L^3 \cdot T^{-6}$

Hence

$a^3 = \frac{x^2 v}{t^5}$ is dimensionally consistent

Considering B

$x = L$

and

$t = T$

Hence

$x = t$ is not dimensionally consistent

Considering C

$v = LT^{-1}$

and

$\frac{x^2 }{at^3} = \frac{L^2}{LT^{-2} T^{3}} = LT^{-1}$

Hence

$v = \frac{x^2}{at^3}$ is dimensionally consistent

Considering D

$xa^2 = L(LT^{-2})^2 = L^3T^{-4}$

and

$\frac{x^2v}{t^4} = \frac{L^2(LT^{-1})}{ T^5} = L^3 T^{-5}$

Hence

$xa^2 = \frac{x^2v}{t^4}$ is not dimensionally consistent

Considering E

$x = L$

;

$vt = LT^{-1} T = L$

and

$\frac{vt^2}{2} = LT^{-1}T^{2} = LT$

Hence

$E \ \ \ x = vt+ \frac{vt^2}{2}$ is not dimensionally consistent

Considering F

$x = L$

and

$3vt = LT^{-1}T = L$ Note in dimensional analysis numbers are

not considered

Hence

$F \ \ \ x = 3vt$ is dimensionally consistent

Considering G

$v = LT^{-1}$

and

$at = LT^{-2}T = LT^{-1}$

Hence

$G \ \ \ v = 5at$ is dimensionally consistent

Considering H

$a = LT^{-2}$

,

$\frac{v}{t} = \frac{LT^{-1}}{T} = LT^{-2}$

and

$\frac{xv^2}{2} = L(LT^{-1})^2 = L^3T^{-2}$

Hence

$H \ \ \ a = \frac{v}{t} + \frac{xv^2}{2}$ is not dimensionally consistent

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2 years ago

Collete mapped her vegetable garden on the graph below. Each unit represents 1 foot.

ipn [44]

Answer:HMMMMM I don’t really know

Step-by-step explanation:

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2 years ago

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