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Katyanochek1 [597]
2 years ago
12

Malia is placing a barrier around the edge of a circular path with a diameter of 13 meters. The barriers are in lengths of 2.5 m

eters. What is the best approximation of how many pieces of barrier Malia will need? Use 3.14 to approximate for π .
Mathematics
2 answers:
alekssr [168]2 years ago
6 0

Answer: 17 is the answer

Can I get brainliest pls

gizmo_the_mogwai [7]2 years ago
5 0

we need some barriers such that total of length of all barriers should equal to the circumference of the circle.

so lets assume we need x barriers

then total length of all barriers = 2.5x meter

now radius of circular path = diameter / 2= 13/2 = 6.5 meter

circumference of path = 2× pi × r = 2 × 3.14 × 6.5

=40.82 meter

so now as per statement

2.5x = 40.82

x = 40.82/2.5 = 16.328 ≈ 17

so approximately 17 barriers are required

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kondaur [170]

Answer:

the probability that the exceeded 65 = 0.3707

The average score of the 36 golfers exceeded 65

                        = 36 X 0.3707 = 13.3452

Step-by-step explanation:

<u>Step 1</u>:-

The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.

mean (μ) = 64

standard deviation (σ) =3

by using normal distribution

given (μ) = 64 and  (σ) =3

i) when x =65

z = \frac{x-mean}{S.D} = \frac{65-64}{3} = 0.33 >0

P( X≥ 65) = P(z≥0.33)

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              = 0.5 - 0.1293 (see normal table)

             = 0.3707

The average score of the 36 golfers exceeded 65

                        = 36 X 0.3707 = 13.3452

                                               

6 0
2 years ago
An electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are l
Tju [1.3M]

Answer:

Step-by-step explanation:

given that an  electrical engineer has on hand two boxes of resistors, with five resistors in each box. The resistors in the first box are labeled 10 ohms, but in fact their resistances are 9, 10, 11, 12, and 13 ohms. The resistors in the second box are labeled 20 ohms, but in fact their resistances are 18, 19, 20, 21, and 22 ohms. The EE chooses one resistor from each box and determines the resistance of each

Sample space for selecting one resistor from first box

= {9, 10, 11, 12, 13}

A = {11,12,13} (because >10)

Sample space for selecting one resistor from second  box

={18,19,20,21,22}

B={18}

Sample space for sum would be

{27, 28, 29, 30, 31, 32, 33, 34, 35}

C = {(9,19) , (10,18)}

8 0
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makkiz [27]

Answer:

Volume of prism = 3,240 cm³

Step-by-step explanation:

GIven.

Hexagonal prism.

Side of base(b) = 12cm

Height of prism = 9cm

Height of base (h)= 10cm

Find:

The volume of the prism.

Computation:

Area of base of hexagonal prism = n/2[bh]

Area of base of hexagonal prism = 6/2[(12)(10)]

Area of base of hexagonal prism = 360 cm²

The volume of prism = Area of base of hexagonal prism × Height of prism

The volume of prism = 360 × 9

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3 0
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Brrunno [24]

The answer is 6(0.65-t)

3 0
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Explain how knowing 1+7 helps you find the sum for 7+1
kakasveta [241]

We can use the concept of commutative property of addition here. We know that the addition follow the commutative property.

The commutative property of addition is given by

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It means, if we change the order, it will not affect the result.

Therefore, using above mentioned property, we can see that

1+7 = 7+1

Hence, if we know the value of 1+7, then we can easily find the value of 7+1 because both are same.

4 0
2 years ago
Read 2 more answers
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