Answer:
Please see attachment
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1 answer:
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The complete question in the attached figure
we know that
find the square of the speeds of individual particles
2.8²----> 7.84
3.2²---->10.24
5.8²----> 33.64
7.3²----> 53.29
7.4²---> 54.76
average=[7.84+10.24+33.64+53.29+54.76]/5-----> 159.77/5----> 31.954
step 2
find the square root of the average
√31.954=5.65
therefore
the answer is
the option b) 5.7 m/s
we know that
the root mean square speed, is the square root of the average (mean) of all of the square of the speeds of individual particles in a gas.
step 1find the square of the speeds of individual particles
2.8²----> 7.84
3.2²---->10.24
5.8²----> 33.64
7.3²----> 53.29
7.4²---> 54.76
average=[7.84+10.24+33.64+53.29+54.76]/5-----> 159.77/5----> 31.954
step 2
find the square root of the average
√31.954=5.65
therefore
the answer is
the option b) 5.7 m/s
Answer:
We have to find the maximum number of solutions of each of the following system:
1)
Two distinct concentric circles:
Since, distinct concentric circles means that the two circles have same center but different radius.
That means they will never intersect each other at any point.
Ans hence we will get zero solutions.
2)
Two distinct parabolas:
Two parabolas can maximum intersect at 2 points this could be seen by the diagrams.
3)
A line and a circle.
A line and a circle can maximum have 2 solutions.
4)
A parabola and a circle.
It can have maximum two solutions it can be seen from the diagram.
