the value of x in this system of equations is 1. 3x y = 9 y = –4x 10 substitute the value of y in the first equation: combine li
2 answers:
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To graph it, just graph 
and 
and see where they intersect
I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it
hmm
multiply both sides by -1
multiply both sides by
minus 1 from both sides and minus 6(3^x) from both sides
use u subsitution
we can rewrite it as
now factor
I mean use quadratic formula
for
so for 0=u^2-16u-1, a=1, b=-16, c=-1
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
if you take the log base 3 of both sides you get
if you use ln then
then
I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it
hmm
multiply both sides by -1
multiply both sides by
minus 1 from both sides and minus 6(3^x) from both sides
use u subsitution
we can rewrite it as
now factor
I mean use quadratic formula
for
so for 0=u^2-16u-1, a=1, b=-16, c=-1
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
if you take the log base 3 of both sides you get
if you use ln then
then
Answer:
Part a)
Part b) The coordinates of the point are
Step-by-step explanation:
Part a) Find the equation representing the ladder
we have the ordered pairs
(0,4) and (2,0)
Find the slope
Find the equation of the line in slope intercept form
we have
substitute
Part b) A square box just fits under the ladder.Find the coordinates of the point where the box touches the ladder.
If the box is a square
the x-coordinate of the point where the box touches the ladder must be equal to the y-coordinate
x=y
substitute
therefore
The coordinates of the point are