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oksano4ka [1.4K]
2 years ago
13

Combine these radicals. √27- √3

Mathematics
2 answers:
Alex73 [517]2 years ago
8 0
Square root 27 is 3squer root 3 so the answer is 2 square root three
mixas84 [53]2 years ago
5 0

\sqrt{9 \times 3}  -   \sqrt{3} \\ 3 \sqrt{3}  -  \sqrt{3}  \\ 2 \sqrt{3}
combined
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2485.97 would be what he earned as an interest rate. The percentage would be6%

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Chen is bringing fruit and veggies to serve at an afternoon meeting. He spends a total of $28.70 on 5 pints of cut veggies and 7
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The answer would be $1.75 (Rounded off to the nearest cent).

Substitute the given cost of each pint of fruit to the equation. Transpose and simplify, to get the price of a pint of veggies.
Given: <span>5v + 7f = 28.70; f = $2.85
Solution: </span><span>5v + 7(2.85) = 28.70
                </span><span>5v + 19.95 = 28.70
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On a december day, the probability of snow is .30. the probability of a "cold" day is .50. the probability of snow and "cold" we
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The extract of a plant native to Taiwan has been tested as a possible treatment for Leukemia. One of the chemical compounds prod
True [87]

Answer:

a) 57.35%

b) 99.99%

c) 68.27%

Step-by-step explanation:

When we have a random variable X that is normally distributed with mean \large\bf \mu and standard deviation \large\bf \sigma, then  

The probability that the random variable has a value less than a, P(X < a) = P(X ≤ a) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma to the left of a.

The probability that the random variable has a value greater than b, P(X > b) = P(X ≥ b) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma to the right of b.

The probability that the random variable has a value between a and b, P(a < X < b) = P(a ≤ X ≤  b) = P(a < X ≤  b)= P(a ≤ X < b) is the area under the normal curve with mean \large\bf \mu and standard deviation \large\bf \sigma between a and b.

In this case, the random variable is the collagen amount found in the extract of the plant. The mean is 63 g/ml and the standard deviation is 5.4 g/ml

(a) What is the probability that the amount of collagen is greater than 62 grams per mililiter?

As we have seen, we need to find the area under the normal curve with mean 63 and standard deviation 5.4 to the right of 62 (see picture).

You can find this value easily with a calculator or a spreadsheet. If you prefer the old-style, then you have to standardize the values and look up in a table.

<em>If you have access to Excel or OpenOffice Calc, you can find this value by introducing the formula: </em>

<em>1- NORMDIST(62,63,5.4,1) in Excel </em>

<em>1 - NORMDIST(62;63;5.4;1) in OpenOffice Calc </em>

<em>and we will get a value of 0.5735 or 57.35% </em>

(b) What is the probability that the amount of collagen is less than 90 grams per mililiter?

Now we want the area to the left of 90

<em>NORMDIST(90,63,5.4,1) in Excel </em>

<em>NORMDIST(90;63;5.4;1) in OpenOffice Calc </em>

You will get a value of 0.9999 or 99.99%

(c) What percentage of compounds formed from the extract of this plant fall within 1 standard deviations of the mean?

You can use either the rule that 68.27% of the data falls between \large\bf \mu -\sigma and \large\bf \mu +\sigma or compute area between 63 - 5.4 and 63 + 5.4, that is to say, the area between 57.6 and 68.4  

<em>In Excel </em>

<em>NORMDIST(68.4,63,5.4,1) - NORMDIST(57.6,63,5.4,1)  </em>

<em>In OpenOffice Calc  </em>

<em>NORMDIST(68.4;63;5.4;1) - NORMDIST(57.6;63;5.4;1)  </em>

In any case we get a value of 0.6827 or 68.27%

3 0
2 years ago
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