Given:
Card A - 1,879.58 ; APR 14%; monthly -43.73
Card B - 861.00 ; APR 10% ; monthly -18.29
5 years x 12 months/yr = 60 months.
Card A = 43.73 x 60 = 2,623.80
Card B = 18.29 x 60 = 1,097.40
Total : 2,623.80 + 1,097.40 = 3,721.20
Lowest APR is 10%. monthly rate: 0.83%
Total Card balance: 1,879.58 + 861 = 2,740.58
A = P * (r(1+r)^n) / [(1+r)^n -1]
A = 2,740.58 * [0.0083 (1.0083)^60] / [(1.0083)^60 - 1]
A = 2,740.58 * 0.014/0.64
A = 2,740.58 * 0.022
A = 60.29 monthly payment.
60.29 x 60 = 3,617.40
Separate cards: 3,721.20
Consolidated: 3,617.40
Difference: 103.80
The closest among the choices is Choice C. 105. Difference in amount may vary in the rounding off of the decimal numbers.
Answer:
The observed tumor counts for the two populations of mice are:
Type A mice = 10 * 12 = 120 counts
Type B mice = 13 * 12 = 156 counts
Step-by-step explanation:
Since type B mice are related to type A mice and given that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12, we can then assume that the mean of type A mice tumor count rate is equal to the mean of type B mice tumor count rate.
This is because the Poisson distribution can be used to approximate the the mean and variance of unknown data (type B mice count rate) using known data (type A mice tumor count rate). And the Poisson distribution gives the probability of an occurrence within a specified time interval.
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.
Number of sample, n = 400
Mean, u = $25,000
Standard deviation, s = $2,500
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z × standard deviation/√n
It becomes
25000 ± 1.96 × 2500/√400
= 25000 ± 1.96 × 125
= 25000 ± 245
The lower end of the confidence interval is 25000 - 245 =24755
The upper end of the confidence interval is 25000 + 245 = 25245
Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245
Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe,
= 120 cm
Its wavelength
= 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒
⇒ 
⇒
⇒ 
⇒
⇒ 
⇒
⇒
So the pipe is open at one end and closed at one end
.
Answer:
11.58%
Step-by-step explanation:
The initial volume if blood flowing through the artery is given by

To achieve a new volume of 155% (55% increase) of the initial volume, the new radius must be:
![V'= 1.55V\\1.55V=k(r')^4\\1.55kr^4 = k(r')^4\\(\sqrt[4]{1.55}*r)^4=(r')^4 \\(1.1158*r)^4=(r')^4 \\r'=1.1158*r](https://tex.z-dn.net/?f=V%27%3D%201.55V%5C%5C1.55V%3Dk%28r%27%29%5E4%5C%5C1.55kr%5E4%20%3D%20k%28r%27%29%5E4%5C%5C%28%5Csqrt%5B4%5D%7B1.55%7D%2Ar%29%5E4%3D%28r%27%29%5E4%20%5C%5C%281.1158%2Ar%29%5E4%3D%28r%27%29%5E4%20%5C%5Cr%27%3D1.1158%2Ar)
Since the new radius is 1.1158 times larger than the initial radius, the percentage increased is:
