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sergeinik [125]
2 years ago
15

It takes Wayne 1/10 hours to walk a 1/6 mile park loop. What is Wayne's unit rate, in miles per hour

Mathematics
1 answer:
olchik [2.2K]2 years ago
5 0
To solve this problem, we should set up a proportion, letting x represent our unknown number of miles that Wayne walks in one hour.

1/6 mile / 1/10 hours = x miles / 1 hour

Now we use cross-products or the multiplication of the numerator of one fraction times the denominator of the other fraction, setting these two numbers equal.  The resulting equation is:

1/6 = 1/10x

Finally, we must divide both sides by 1/10 to cancel it out on the right side of the equation and get the variable x alone.

x = 5/3 or 1 2/3

Therefore, Wayne walks 1 2/3 miles per hour.
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A recent survey in the N.Y. Times Almanac indicated that 48.8% of families own stock. A broker wanted to determine if this surve
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Answer:

There is enough statistical evidence to support the claim that the survey is not accurate.

Step-by-step explanation:

We have  to perform a test of hypothesis on the proportion.

The claim is that the proportion of families that own stock differs from 48.8%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.488\\\\H_a:\pi\neq0.488

The significance level is 0.05.

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p=X/n=142/250=0.568

The standard error of the proportion is

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.488*0.512}{250}}=\sqrt{0.00099}=0.032

The z-statistic can now be calculated:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.568-0.488-0.5/250}{0.032}=\dfrac{0.078}{0.032}=2.4375

The P-value for this two-tailed test is then:

P-value=2*P(z>2.4375)=0.015

As the P-value is smaller than the significance level, the effect is significant. The null hypothesis is rejected.

There is enough evidence to support the claim that the survey is not accurate.

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2 years ago
Point F is on circle C.
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Choice D

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