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1 year ago

It takes Wayne 1/10 hours to walk a 1/6 mile park loop. What is Wayne's unit rate, in miles per hour

1 answer:

5 0

To solve this problem, we should set up a proportion, letting x represent our unknown number of miles that Wayne walks in one hour.

1/6 mile / 1/10 hours = x miles / 1 hour

Now we use cross-products or the multiplication of the numerator of one fraction times the denominator of the other fraction, setting these two numbers equal. The resulting equation is:

1/6 = 1/10x

Finally, we must divide both sides by 1/10 to cancel it out on the right side of the equation and get the variable x alone.

x = 5/3 or 1 2/3

Therefore, Wayne walks 1 2/3 miles per hour.

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the answer is B. good luck

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2 years ago

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2 years ago

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1 year ago

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Answer:

D. insufficient data

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1 year ago

A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x

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Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

That would be number of units sold to get max revenue.

Then we take that "x" value and substitute into r(x) to get the max revenue amount.

Before differentiating, we see the rules shown below:

$f(x)=ax^n\\f'(x)=n*ax^{n-1}$

Where

f'(x) is the differentiated function

Now, let's do the process:

$r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000$

So, 1000 units need to be sold for max revenue

Now, substituting, we get:

$r (x)=700x-0.35x^2\\r(1000)=700(1000)-0.35(1000)^2\\r(1000)=350,000$

The max revenue amount is $350,000

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1 year ago