Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week. With a full tank
1 answer:
Answer:
50 miles.
Step-by-step explanation:
Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week.
With a full tank of gas he can drive 100 miles.
Question asked:
How many miles can he drive on the weekend, before he he fills up again?
Solution:
With full tank he can drive a total distance = 100 miles
Each day of the work week, he drives = 10 miles
Total miles, he drive in whole work week (Monday - Friday) =
<em>Now, to find that many miles he can drive on the weekend (Saturday and Sunday), we will subtract total miles, he drive in whole work week from the total distance, he can drive with full tank of gas:-</em>
100 - 50 = 50 miles.
Therefore, he can drive 50 miles on the weekend, before he he fills up again.
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Now we check the x intercepts of the first graph
x intercepts of first graph is -4 and 2
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Hence first option is the graph of
Answer:
a) Null and alternative hypothesis
b) Test statistic t=-1.565
P-value = 0.0612
NOTE: the sample size is n=65.
c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
d) Null and alternative hypothesis
Test statistic t=-1.565
Critical value tc=-1.669
t>tc --> Do not reject H0
Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=65.
The sample mean is M=30.15.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.
The estimated standard error of the mean is computed using the formula:
Then, we can calculate the t-statistic as:
The degrees of freedom for this sample size are:
This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):
As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
<u>Critical value approach</u>
<u></u>
At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.
As the test statistic is greater than the critical value, it falls in the acceptance region.
The null hypothesis failed to be rejected.