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2 years ago

A two pound box of fruit snacks contains 24 packets. Find the unit rate in packets per pound

Mathematics

2 answers:

Monica [59]2 years ago

6 0

24/2=12

The unit rate is 12 packets per pound.

Hope this helps!

Evgesh-ka [11]2 years ago

6 0

Answer:

Step-by-step explanation:

Given that a two pound box of fruit snacks contains 24 packets

We have to find the unit rate per pound

This is a question of direct variation.

$2 pounds = 24 packets\\1 pount= 12 packet$

i.e. unit rate is 12 packets per pound

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Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o

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Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)± $t_{n_1+n_2-2}$ * $Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$

$t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71$

[(33.99-26.56) ± 1.654 *( $3.71*\sqrt{\frac{1}{135} +\frac{1}{42} }$ )]

[6.345; 8.514]= [6.35; 8.51]km/h

Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15

$t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{11*(43.48)^2+14*(21.60)^2}{12+15-2} } = 33.06$

[(475.12-321.34) ± 2.485 *( $33.06*\sqrt{\frac{1}{12} +\frac{1}{15} }$ )]

[121.96; 185.60]

I hope this helps!

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2 years ago

Two spheres of the same density have a ratio of 4 to 9 in surface area. If the small sphere weighs 10 kg, what does the large sp

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w= 33.75, the weight of the larger sphere

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2 years ago

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Answer:

B) 5 (x minus 3)

C) 4 x + 3 y minus 15 minus 3 y + x

E) Negative 20 minus 3 x + 5 + 8 x

tep-by-step explanation:

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4x + 3y - 15 - 3y + x

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-20 - 3x + 5 + 8x

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The average lethal blood concentration of morphine is estimated to be 2.5 µg/mL with a standard deviation of 0.95 µg/mL. The dat

dmitriy555 [2]

Answer:

The probability associated with the range lethal morphine blood levels is 0.9902.

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Let X = lethal blood concentration of morphine.

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Compute the probability of X within the range 0.05 to 4.95 μg/ mL as follows:

$P(0.05$

*Use a z-table for the probability.

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