If you have 20 square<span> pieces of wood, describe all the different ways you could make a rectangle by placing them side by side.</span><span>
1X20, 2X10, 4X5</span>
Answer:
<em>2,300,000pages report.</em>
Step-by-step explanation:
Given a USB drive with memory of 4.6*10⁶KB, in order to know the maximum number of pages a report can have so that it can be completely stored on the drive, the conversion factor must be used.
We must first understand that 1 page of a document uses up approximately 2kB of the storage.
Since 2kB = 1page
4.6*10⁶KB = x page
Cross multiply
2kB * x = 4.6*10⁶KB * 1
2x = 4.6*10⁶
x = 4.6*10⁶/2
x = 2.3*10⁶
x = 2,300,000
<em>Hence the maximum number of pages that the report can have so that it can be completely stored on a USB drive that holds 4.6*10⁶KB is approximately 2,300,000pages report.</em>
B + N = 18 and 6B + 5N = 101. This is the system of equations you would use.
Answer:
22
Step-by-step explanation:
Solve the inequality (20 + 0.5x) + 0.15(20 + 0.5x) ≤ $62.10 for x:
20 + .5x + 3 + 0.75x ≤ 62.10
Combining the x terms, we get:
20 + 3 + 1.25x ≤ 62.10.
Combining the constants on the left:
23 + 1.75x ≤ 62.10
Combining the constants:
1.75x = 39.10
Solving for x: 39.10/1.75 = 22.34
Thus, the max number of whole pages she can have in her book is 22.
Answer:
we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years
Step-by-step explanation:
Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.
Let X be the group married less than 2 years and Y less than 5 years
X Y Total
Sample size 300 300 600
Favouring 240 288 528
p 0.8 0.96 0.88

p difference = -0.16
Std error for difference = 
Test statistic = p difference/std error=-6.03
p value <0.000001
Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years