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1 year ago

12

Drag each interval to a box to show if the function shown is increasing, decreasing, or neither over that interval.

2 answers:

prisoha [69]1 year ago

8 0

Answer:

Increasing

−5<x<−1

−1<x<1

Decreasing

4<x<7

−8<x<−5

Neither Increasing nor Decreasing

1<x<4

Step-by-step explanation:

kenny6666 [7]1 year ago

5 0

Answer:

Increasing : $-5$ or $-1$

Decreasing : $-8$ or $4$

Neither : $1$

Step-by-step explanation:

Increasing function : In this function, the y-value increases as the x-value increases.

From the given graph it is clear that the function is increasing on

$-5$

$-1$

Decreasing function : In this function, the y-value decreases as the x-value increases.

From the given graph it is clear that the function is decreasing on

$-8$

$4$

Neither increasing nor decreasing function : In this function, the y-value remains constant as the x-value increases.

From the given graph it is clear that the function is neither increasing nor decreasing on

$1$

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What is a simplified form of -(14x)^0y^-7z

GenaCL600 [577]

Anything to the power of 0 is one.

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(1)(y^-7z)

Which simplifies to:

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2 years ago

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The average lifetime of a certain new cell phone is 3.4 years. The manufacturer will replace any cell phone failing within three

melisa1 [442]

Answer:

68% of these phones last 3.87 years.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The average lifetime of a certain new cell phone is 3.4 years.

This means that $m = 3.4, \mu = \frac{1}{3.4} = 0.2941$

So

$P(X \leq x) = 1 - e^{-0.2941x}$

68% of these phones last how long (in years)?

This is x for which:

$P(X \leq x) = 0.68$

$P(X \leq x) = 1 - e^{-0.2941x}$

Then

$0.68 = 1 - e^{-0.2941x}$

$e{-0.2941x} = 0.32$

$\ln{e{-0.2941x}} = \ln{0.32}$

$-0.2941x = \ln{0.32}$

$x = -\frac{\ln{0.32}}{0.2941}$

$x = 3.87$

68% of these phones last 3.87 years.

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1 year ago

A meteorologist is studying the monthly rainfall in a section of the Brazilian rainforest. She recorded the monthly rainfall, in

Andreyy89

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= 84 / 12 = 7
Median
Arrange the numbers from least to greatest
1.8, 2.5, 2.6, 4.4, 4.4, 7.3, 8.0, 9.5, 10.3, 10.4, 11.1, 11.7
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Mode: Which among the numbers appear more frequently. That is 4.4

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2 years ago

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An automobile manufacturer claims that its car has a 42.8 miles/gallon (MPG) rating. An independent testing firm has been contra

yanalaym [24]

Answer: -1.51

Step-by-step explanation:

Let $\mu$ be the population mean rating of car.

As per given , we have

$H_0: \mu=42.8$

$H_a: \mu\neq42.8$

Since population variance is known, so we use z-test.

Test statistic : $z=\dfrac{\overline{x}-\mu}{\sqrt{\dfrac{\sigma^2}{n}}}$

, where n= sample size

$\overline{x}$ = Sample mean

$\sigma^2$ = variance

As per given ,

n=300

$\overline{x}=42.6$

$\sigma^2=5.29$

$\mu=42.8$

Put these values in formula we get

$z=\dfrac{42.6-42.8}{\sqrt{\dfrac{5.29}{300}}}$

$z=\dfrac{-0.2}{\sqrt{0.0176333}}$

$z=\dfrac{-0.2}{0.13279}=-1.50613751035\approx1.51$

Hence, the value of the test statistic is z= -1.51 .

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2 years ago