Answer: -2.145
Step-by-step explanation:
(3.2+4x)+(18.25+6x)=
Simplifying
(3.2 + 4x) + (18.25 + 6x) = 0
Remove parenthesis around (3.2 + 4x)
3.2 + 4x + (18.25 + 6x) = 0
Remove parenthesis around (18.25 + 6x)
3.2 + 4x + 18.25 + 6x = 0
Reorder the terms:
3.2 + 18.25 + 4x + 6x = 0
Combine like terms: 3.2 + 18.25 = 21.45
21.45 + 4x + 6x = 0
Combine like terms: 4x + 6x = 10x
21.45 + 10x = 0
Solving
21.45 + 10x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-21.45' to each side of the equation.
21.45 + -21.45 + 10x = 0 + -21.45
Combine like terms: 21.45 + -21.45 = 0
0 + 10x = 0 + -21.45
10x = 0 + -21.45
Combine like terms: 0 + -21.45 = -21.45
10x = -21.45
Divide each side by '10'.
x = -2.145
Simplifying
x = -2.145
Answer with Step-by-step explanation:
We are given that

For each real number 
To prove that f is one -to-one.
Proof:Let
and
be any nonzero real numbers such that

By using the definition of f to rewrite the left hand side of this equation

Then, by using the definition of f to rewrite the right hand side of this equation of 

Equating the expression then we get




Therefore, f is one-to-one.
Given:
Cost of four lines = $125
Cost of each additional line = $15
Jason wants to spend at most $200 per month on cell phone expenses.
To find:
The inequality for the given situation.
Solution:
Let
be the number of additional line.
Cost of one additional line = $15
Cost of
additional line = 
Total cost = Fixed cost + Addition cost
= 
It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

Therefore, the correct option is C.
Answer:
-1.14
Step-by-step explanation:
The given information in statement is
mean=μ=69
standard deviation=σ=3.5
Let X be the Ishaan's exam score
X=65
The Z score can be computed as


z=-1.1429
z=-1.14 (rounded to two decimal places).
Thus, the computed z-score for Ishaan's exam grade is -1.14.
Answer:
Step-by-step explanation:
The best option is for the consultant to remove these data points because they are outliers. Unusual data points which are located far from rest of the data points are known as outliers.