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2 years ago

8

Nikki had a $50 gift card for her favorite store. She used the gift card to buy 4 DVDs and still had money available on the card

after the purchase. If the DVDs were all the same price, which inequality best represents the possible price of each DVD? a.. p greater-than 12.50 b.. p greater-than-or-equal-to 12.50 c.. p less-than 12.50 d.. p less-than-or-equal-to 12.50

2 answers:

grandymaker [24]2 years ago

7 0

Answer:

c

Step-by-step explanation:

c because 12.50x4=50 and she still had money left

ASHA 777 [7]2 years ago

5 0

Answer:

it is c

Step-by-step explanation:

i did it myself like a man. (this is for edgenutiy 2020)

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g Students conducted a survey and found out that 36% of their peers on campus had tattoos but only 4% of their peers were smoker

IgorC [24]

Answer:

D) No, because either np or n(1−p) are less than 15.

Step-by-step explanation:

Percentage of students who had tattoos = 36%

Percentage of students who were smokers = 4%

Sample size = n = 100

The condition to use the Normal distribution as an approximation to construct the confidence interval for population proportion is:

Both np and n(1-p) must be equal to or greater than 15.

Since, we are interested in smokers only, so p = 4% = 0.04

np = 100 x 0.04 = 4

n (1 - p) = 100 x 0.96 = 96

Since, np < 15, we cannot use the Normal distribution as an approximation here.

Therefore, the correct answer is:

No, because either np or n(1−p) are less than 15.

5 0

1 year ago

Suppose the Sunglasses Hut Company has a profit function given by P ( q ) = − 0.02 q 2 + 5 q − 30 , where q is the number of tho

Andrew [12]

Answer:

A) Pairs of sunglasses should be sold to maximize profits is 100 thousand.

B) The actual maximum profits that can be expected is 180 thousands dollars.

Step-by-step explanation:

Given : Suppose the Sunglasses Hut Company has a profit function given by $P(q)=-0.02q^2+4q-20$

where, q is the number of thousands of pairs of sunglasses sold and produced and P(q) is the total profit, in thousands of dollars, from selling and producing q pairs of sunglasses.

To find :

A) How many pairs of sunglasses (in thousands) should be sold to maximize profits?

Profit is $P(q)=-0.02q^2+4q-20$

Compare with general quadratic equation $ax^2+bx+c$

a=-0.02, b=4, c=-20

The maximum value of quadratic function is at $x=-\frac{b}{2a}$

So, maximum profit occur at q is given by,

$q=-\frac{4}{2(-0.02)}$

$q=\frac{4}{0.04}$

$q=100$

i.e. 100 thousand pair of sunglasses.

Pairs of sunglasses should be sold to maximize profits is 100 thousand.

B) What are the actual maximum profits (in thousands) that can be expected?

Maximum profit occurs at q=100 thousand pairs is given by,

$P(100)=-0.02(100)^2+4(100)-20$

$P(100)=-0.02\times 10000+400-20$

$P(100)=180$

The actual maximum profits that can be expected is 180 thousands dollars.

7 0

1 year ago

Which cube root function is always decreasing as x increases?

Aleks04 [339]

We know

$y=\sqrt[3]{x}$

is an increasing function as when the value of x increases the value of y increases

And when the value of x decreases , the value of y also decreases.

Now if we have (x+a) or (x-a) instead of x, the function shall have a horizontal shift.

So it shall either move left or right but shall not flip.

So

$y=\sqrt[3]{(x-8)}$ and $y=\sqrt[3]{(x-5)}$

are increasing functions.

Only when x becomes -x, that the function shall flip & shall become a decreasing function.

But then it must be - (x-a) or -(x+a) inside.

So

$y=\sqrt[3]{-(5-x)}$ is also increasing

Only

$y=- \sqrt[3]{(x+5)}$

is a decreasing function.

Option D) is the right answer.

6 0

2 years ago

Read 2 more answers

Data show that men between the ages of 20 and 29 in a general population have a mean height of 69.3 inches, with a standard dev

dangina [55]

Data show that men between the ages of 20 and 29 in a general population have a mean height of 69.3 inches, with a standard deviation of 2.5 inches. a baseball analyst wonders whether the standard deviation of heights of major-league baseball players is less than 2.5 inches. the heights (in inches) of 20 randomly selected players are shown in the table.

72 74 71 72 76

70 77 75 72 72

77 72 75 70 73

74 75 73 74 74

What are the correct hypotheses for this test?

The null hypothesis is H₀?: ____ 2.5

The alternative hypothesis is H₁?: ____ 2.5

Calculate the value of the test statistic.

x² = _____ (Round to three decimal places)

Answer:

Null hypothesis, H₀: σ = 2.5

Alternative hypothesis, Hₐ: μ<2.5

Test statistic = 12.920

Step-by-step explanation:

Given Data shows that:

men between the ages of 20 and 29 in a general population have a mean height of 69.3 inches, with a standard deviation of 2.5 inches

We consider a random sample of 20 selected baseball players.

Therefore;

The Null and Alternative hypothesis are as follows:

The Null hypothesis is the standard deviation of the heights of major league baseball players is not less than 2.5 inches.

Null hypothesis, H₀: σ = 2.5

On the other hand: The Alternative hypothesis is the standard deviation of the heights of major league baseball players is less than 2.5 inches.

Alternative hypothesis, Hₐ: μ<2.5

The Mean Calculation is:

$\bar{x} = \frac{1}{2} \sum x_i$

$= \frac{1}{20} (72+74+...+74) \\ \\ = \frac{1468}{20} \\ \\ =73.4$

The sample standard deviation is:

$s = \sqrt{\frac{1}{n-1} \sum (x_1 - \bar{x})^2 }$

$= \sqrt{\frac{1}{20-1} \sum (72-73.4)^2 + ...+(74-73.4)^2 } \\ \\ = \sqrt{4.25} \\ \\ = 2.06$

The test statistics is now determined as :

$x^2 = \frac{(n-1)s^2}{\sigma^2} \\ \\ = \frac{(20-1)(2.06)^2}{(2.5)^2} \\ \\ = \frac{19*4.25}{6.25} \\ \\ = \frac{80.75}{6.25} \\ \\ = 12.920$

4 0

2 years ago

The constant-pressure specific heat of air at 25°C is 1.005 kJ/kg. °C. Express this value in kJ/kg.K, J/g.°C, kcal/ kg. °C, and

Mice21 [21]

Answer:

In kJ/kg.K - 1.005 kJ/kg degrees Kalvin.

In J/g.°C - 1.005 J/g °C

In kcal/ kg °C 0.240 kcal/kg °C

In Btu/lbm-°F 0.240 Btu/lbm degree F

Step-by-step explanation:

given data:

specific heat of air = 1.005 kJ/kg °C

In kJ/kg.K

1.005 kJ./kg °C = 1.005 kJ/kg degrees Kelvin.

In J/g.°C

$1.005 kJ./kg °C \times 1000/1kJ \times (1kg/1000 g) = 1.005J/g °C$

In kcal/ kg °C

$1.005 kJ./kg °C \times \frac{1 kcal}{4.190 kJ} = 0.240 kcal/kg °C$

For kJ/kg. °C to Btu/lbm-°F

Need to convert by taking following conversion ,From kJ to Btu, from kg to lbm and from degrees C to F.

$1.005 kJ./kg °C \times \frac{1 Btu}{1.055 kJ} \times \frac{0.453 kg}{1 lbm} \times \frac{5/9 degree C}{1 degree F} = 0.240 Btu/ lbm / degree F$

1.005 kJ/kg C = 0.240 Btu/lbm degree F

8 0

2 years ago