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WITCHER [35]
2 years ago
8

Nikki had a $50 gift card for her favorite store. She used the gift card to buy 4 DVDs and still had money available on the card

after the purchase. If the DVDs were all the same price, which inequality best represents the possible price of each DVD? a.. p greater-than 12.50 b.. p greater-than-or-equal-to 12.50 c.. p less-than 12.50 d.. p less-than-or-equal-to 12.50
Mathematics
2 answers:
grandymaker [24]2 years ago
7 0

Answer:

c

Step-by-step explanation:

c because 12.50x4=50 and she still had money left

ASHA 777 [7]2 years ago
5 0

Answer:

it is c

Step-by-step explanation:

i did it myself like a man. (this is for edgenutiy 2020)

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Which expression is equivalent to ( xy -6)2 for all values of x and y where the expression is defined?
hichkok12 [17]

Answer:

 ( x y -6)²  =  x² y² - 12 xy + 36            

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the expression ( x y -6)²

Apply formula (a-b)² = a² -2ab + b²

( x y -6)² = (xy)² - 2 × xy× 6 + (6)²

             = x² y² - 12 xy + 36

( x y -6)²  =  x² y² - 12 xy + 36            

4 0
1 year ago
Read 2 more answers
These tables represent a quadratic function with a vertex at (0,3) What us the average rate of change from the interval from x=7
VladimirAG [237]
The rate of change is shown to the right of the second graph as being -2 

At 5 to 6 the average rate of change is -11, so at 6 to 7 the rate of change would be -11-2 = -13, then from 7 to 8 it would be -13-2 = -15.

The answer is D. -15
3 0
2 years ago
Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp
yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

H_0: \mu=2\\\\H_a:\mu< 2

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803

The degrees of freedom for this sample size are:

df=n-1=52-1=51

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0
2 years ago
How is (s-t)(s/t) equivalent to (s^2/t) -s
tigry1 [53]
(s-t)\cdot\dfrac{s}{t}=s\cdot\dfrac{s}{t}-t\cdot \dfrac{s}{t}=\dfrac{s^2}{t}-s
4 0
2 years ago
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Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a
lisov135 [29]
1 mile at 12 m/h is .2 m/min
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1/10=.1 m/min which is 6 m/h
The average speed is 6+12/2=9 m/h

Hope that helps.  Feel free to ask any questions.
5 0
2 years ago
Read 2 more answers
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