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Effectus [21]
2 years ago
11

The sides of a square are three to the power of two sevenths inches long. What is the area of the square? (

Mathematics
1 answer:
____ [38]2 years ago
8 0

Answer:

Step-by-step explanation:

The side of the square = 3^2/7

Use the law of exponents . If the power is a fraction, that means it is

3^2/7 = 3^2 x 1/7 = 7√9

To find the area you multiply this by itself.

This gives you 1.87...

Hope this helps

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If you know that a < b, and both a and b are positive numbers, then what must be true about the relationship between the oppo
Ymorist [56]

Answer:

The number further left on a number line is the smaller number. For positive numbers, the number closest to zero is smaller. For negative numbers, the number closest to zero is larger. If a is less than b, and they are both positive, then a is closer to 0 than b. The opposite of a is also closer to zero than the opposite of b, so the opposite of a must be larger than the opposite of b.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
This confuses me can I some help? Mary's mom gave her $100 to go shopping. She bought a shirt for $22.65 and a skirt $33.31. She
vazorg [7]
I believe the answer would be 49.64 because if you add them together 22.65+33.31 = 55.96 x .10 = 5.60 55.96-5.60 = $49.64
4 0
2 years ago
Read 2 more answers
The staff at a company went from 40 to 29 employees. what is the percent decrease in staff
topjm [15]
Number of employees outside of company=40-29=11

we can calculate the percent decrease in staff by the rule of 3

40 employees-----------------100%
11 employees----------------   x

x=(11 employees*100%) / 40 employees=27.5%

The percent decrease in staff was: 27.5%
5 0
2 years ago
Carbon-141414 is an element that loses about 10\%10%10, percent of its mass every millennium (i.e., 100010001000 years). A sampl
ololo11 [35]

Answer:

Carbon-14 loses around 10% ( 0.1 in decimal form) of its mass, after one millennium.

Then if we start with a mass A of Carbon-14, after one millennium we will have a mass equal to:

A - A*0.1 = A*(0.9)

After another millennium, we will have a mass equal to:

A*(0.9) - A*(0.9)*0.1 = A*(0.9)^2

And so on, this is an exponential decay.

We already can see the pattern here, after x millenniums, the mass of carbon-14 will be:

M(x) = A*(0.9)^x

Now, in this problem we have 600 grams of carbon-14, then the equation for the mass will be:

y = M(x) = 600g*(0.9)^x

And the graph of this equation is shown below.

4 0
2 years ago
Read 2 more answers
Computing if a computer can do one calculation in 0.0000000015 second, then the function t(n) = 0.0000000015n gives the time req
Lelechka [254]

Answer:

t(5,000,000,000) = 7.5 sec

Explanation:

A computer take 0.0000000015 sec to do a calculation.

Given a function t(n) = 0.0000000015n

where n represent the number of calculation.

We need to find the total time computer to do 5 billion calculations.

We plug n = 5 billion = 5,000,000,000

Total taken time t(n) =0.0000000015n

t(5,000,000,000) = (0.0000000015)*(5,000,000,000)

t(5,000,000,000) = 1.5*5

t(5,000,000,000) = 7.5 sec

That's the final answer.

I hope it will help you.



4 0
2 years ago
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