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2 years ago

6

Write 55,426 using the number names

2 answers:

Aleks04 [339]2 years ago

4 0

Answer:

fifty five thousand four hundred and twenty six.

Step-by-step explanation:

Kobotan [32]2 years ago

3 0

Answer:

Hey mate

Step-by-step explanation:

55,426

Fifty five thousand four hundred twenty six.

hope it helps,

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As a laboratory assistant, you measure chemicals using the metric system. For your current research, you need to measure out 45

tankabanditka [31]

There are about 28 grams in an ounce so 45/28 is about 1.5

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2 years ago

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Match the following items by evaluating the expression for x = -6.

Kryger [21]

Step-by-step explanation:

Put the value of x = -6 to all expressions:

$x^{-2}=(-6)^{-2}=\dfrac{1}{(-6)^2}=\dfrac{1}{6}\qquad\text{used}\ a^{-n}=\dfrac{1}{a^n}\\=====================\\x^{-1}=(-6)^{-1}=\dfrac{1}{(-6)^1}=-\dfrac{1}{6}\\=====================\\x^0=(-6)^0=1\qquad a^0=1\ \text{for all real numbers except 0}\\=====================\\x^1=(-6)^1=-6\qquad a^1=a\ \text{for all real numbers}\\=====================\\x^2=(-6)^2=36$

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2 years ago

Given f(x) = 70 + 11x, find x when f(x) =158

Mumz [18]

Answer:

$\huge \boxed{x = 8}$

Step-by-step explanation:

f(x) = 70 + 11x

To find the value of x when f(x) =158 , equate f(x) to 158

We have

$70 + 11x = 158 \\ 11x = 158 - 70 \\ 11x = 88$

Divide both sides by 11

$\frac{11x}{11} = \frac{88}{11} \\$

We have the final answer as

<h3>x = 8</h3>

Hope this helps you

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2 years ago

Alex draws the scale model shown as a plan for a large wall mosaic. 10 cm 12 cm

miskamm [114]

Answer: a

Step-by-step explanation:

7 0

2 years ago

Arrange the entries of matrix A in increasing order of their cofactors values

givi [52]

To find the cofactor of

$A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]$

We cross out the Row and columns of the respective entries and find the determinant of the remaining $2\times 2$ matrix with the alternating signs.

$Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|$

$Ac_{11}=4\times 1- -1\times 2$

$Ac_{11}=4+ 2$

$Ac_{11}=6$

$Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|$

$Ac_{12}=-(-7\times 1- -1\times -8)$

$Ac_{12}=-(-7- 8)$

$Ac_{12}=15$

$Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|$

$Ac_{21}=-(5\times 1- 3\times 2)$

$Ac_{21}=-(5-6)$

$Ac_{21}=1$

$A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|$

$Ac_{23}=-(7\times 2 -8\times 5)$

$Ac_{23}=-(14-40)$

$Ac_{23}=26$

$A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|$

$Ac_{31}=5\times -1 -4\times 3$

$Ac_{31}=-5-12$

$Ac_{31}=-17$

$A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|$

$Ac_{33}=7\times 4- -7\times 5$

$Ac_{33}=28+35$

$Ac_{33}=63$

Therefore in increasing order, we have;

$Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63$

7 0

2 years ago

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