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Molodets [167]
2 years ago
6

Write 55,426 using the number names

Mathematics
2 answers:
Aleks04 [339]2 years ago
4 0

Answer:

fifty five thousand four hundred and twenty six.

Step-by-step explanation:

Kobotan [32]2 years ago
3 0

Answer:

Hey mate

Step-by-step explanation:

55,426

Fifty five thousand four hundred twenty six.

hope it helps,

mark me as the brainliest,

follow me

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Then, 15 - x is the distance ran in the second part.
The time, t1, for the first part is t1 = xmi / 8mi/h
The time, t2, for the second part is t2 = (15 - x)mi / 20mi/h
The total time is t1 + t2 = 1.125 h
Then x/8 + (15 - x) / 20 = 1.125
To solve for x, multiply both sides by 40 (this is the least common multiple)
5x + 30 - 2x = 45
3x = 15

to find x divide: 15/3=5

And 15 - x = 10 mi.
First part:
Speed: 8mi/h
Distance: 5 mi
Time: 5mi/8mi/h = 5/8 h = 37.5 minutes
Second part
Speed: 20 mi/h
Distance: 10 mi
Average speed: 15mi/1.125h =13.33 mi/h
Distance: 15mi
Time: 1.125 h = 67.5 minutes 
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2 years ago
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Can you Solve this?<br> IF AT=4 CAT=6 CROW=8 BRAIN=10<br><br> TWISTER = ?
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The answer is 14 there just adding an extra letter each time twister has 7 letters
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A stadium brings in $16.25 million per year. it pays football-related expenses of $13.5 million and stadium expenses of $2.7 mil
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We have that

Profit margin is calculated by finding the net profit as a percentage of the revenue

Profit margin = [Net profit / Revenue]

Net profit= [Revenue-Cost]

we know that

Revenue = $16.25 million

Cost = $13.5 million + $2.7 million

Net profit = [16.25 million - (13.5 million + 2.7 million)]

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Profit margin = 0.05 / 16.25

Profit margin = 0.003077 or 0.3077%


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Mrs. Blackwell gives each of her students two pencils. How many pencils did she hand out?
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Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



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2 years ago
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