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AleksAgata [21]
2 years ago
7

Alex draws the scale model shown as a plan for a large wall mosaic. 10 cm 12 cm

Mathematics
1 answer:
miskamm [114]2 years ago
7 0

Answer: a

Step-by-step explanation:

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The expression 0.15c-0.072 factored is ​
Pavlova-9 [17]

Answer:

0.15c-0.072

divide both side by 0.15c

then simplify by the answer then you will get your answer

Step-by-step explanation:

0.15c-0.072

divide both side by 0.15c

then simplify by the answer then you will get your answer

4 0
2 years ago
Draw the number 24 then draw a quick picture to show 24 after you have to regrouped 1 ten as 10 ones explain how both pictures s
Vesnalui [34]
First draw 24 shapes of your choice.

Then, in a different space or below those 24 shapes, draw 10 more shapes twice. So draw 10 shapes and draw 10 more next to them. Finally, draw 4 more shapes with space between them and say "10+10+4=24"
6 0
2 years ago
If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?
Airida [17]

Answer:

\dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}

Step-by-step explanation:

We know that for any two function f(x) and g(x) ,

\dfrac{f}{g}(x)=\dfrac{f(x)}{g(x)}

Given functions : r(x)=3x-1  and s(x)=2x+1

Then, \dfrac{r}{s}(x)=\dfrac{r(x)}{s(x)}

\Rightarrow\ \dfrac{r}{s}(x)=\dfrac{3x-1}{2x+1}

At x= 6 , we get

\dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}

The , The expression is equivalent to \dfrac{r}{s}(6)=\dfrac{3(6)-1}{2(6)+1}

When we further simplify it , we get \dfrac{r}{s}(6)=\dfrac{18-1}{12+1}=\dfrac{17}{13}

5 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each equation with the operation yo
Tanzania [10]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

-15u^3 + 5u^3=-10u^3

2.  10u^3 +(-5u^3)

Adding

10u^3-5u^3=5u^3

3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

Two separate ways to find the answers.

7 0
2 years ago
Read 2 more answers
Choose all sequences of transformations that produce the same image of a given figure.
elena-14-01-66 [18.8K]

<em><u>Your answer: </u></em> a reflection across the y-axis followed by a clockwise rotation 90° about the origin. A clockwise rotation 90° about the origin followed by a reflection across the x-axis. A counter-clockwise rotation 90° about the origin followed by a reflection across the y-axis. A reflection across the x-axis followed by a counter-clockwise rotation 90° about the origin.

Hope this helps <3

Stay safe

Stay Warm

-Carrie

Ps. It would mean a lot if you marked this brainliest

5 0
2 years ago
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