Answer:
Longest possible length for each of the shorter lengths of ribbon is 9 cm because greatest common factor for both 36 and 45 is 9.
Step-by-step explanation:
Alannah has two ribbons one length is 36cm and other is 45cm.
It asked to find shorter length of ribbons that each cut into equal pieces with out no ribbon left over.
So, let's find greatest common factor for both 36 and 45.
Let's prime factor each number
36= 2*2*3*3
45= 3*3*5
So, GCF is product of common factors for both numbers.
GCF= 3*3 =9
So, longest possible length for each of the shorter lengths of ribbon is 9 cm.
Learn more about GCF in brainly.com/question/21612147.
Answer: Kai
Step-by-step explanation:
I did the assignment and got it correct
Let x = weight of adult meerkat, y=weight of baby meerkat, Find y.
x=0.776 kg
y+7.47hectogram=x=0.776
Since 1 hectogram = 0.1 kg,
Therefore the weight of baby meerkat is, y= 0.029 kg
Answer:
Step-by-step explanation:
hello :
100+(n-2)² = 149
100-100+(n-2)² = 149-100
(n-2)² = 49
(n-2)² - 49 =0 but 49=7²
(n-2)² - 7² =0 use identity : a²-b²=(a-b)(a+b)
(n-2-7)(n-2+7)=0
(n-9)(n+5)=0
n-9=0 or n+5=0
n=9 or n=-5
6 total beads
1 is yellow
1 is blue
1/6 of getting a yellow
1/6 of getting a blue and
1/6 of getting a yellow again
1/6 * 1/6 * 1/6 = 1/216 probability
