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vovikov84 [41]
2 years ago
15

Match the following items by evaluating the expression for x = -6.

Mathematics
1 answer:
Kryger [21]2 years ago
5 0

Step-by-step explanation:

Put the value of x = -6 to all expressions:

x^{-2}=(-6)^{-2}=\dfrac{1}{(-6)^2}=\dfrac{1}{6}\qquad\text{used}\ a^{-n}=\dfrac{1}{a^n}\\=====================\\x^{-1}=(-6)^{-1}=\dfrac{1}{(-6)^1}=-\dfrac{1}{6}\\=====================\\x^0=(-6)^0=1\qquad a^0=1\ \text{for all real numbers except 0}\\=====================\\x^1=(-6)^1=-6\qquad a^1=a\ \text{for all real numbers}\\=====================\\x^2=(-6)^2=36

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the trinomial x2 bx c factors to (x m)(x n). if b is negative and c is positive, what must be true about m and n?
galina1969 [7]

For c to be positive, and for b to be negative, m must be negative and n must be negative.


X^2 - bx + c = (x - m)(x - n).

c is the product of m and n. If both m and n are positive, c would be positive. However b is the sum of m and n, therefore to make b negative, both m and n must be negative to ensure that the product of m and n is positive


7 0
2 years ago
Read 2 more answers
Twice a year, for all four years of college, you used your credit card to pay for books and supplies, which amounts to $516 a se
mixer [17]

Answer:

$11,728

Step-by-step explanation:

Twice a year, for 4 years is 8 times

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4 0
2 years ago
On the first day of a family road trip, Kai's family travels 365 miles.
Gekata [30.6K]
They traveled 292 miles on day two.

Known: On the first day they traveled 365 and on the second they traveled 20% less.

Solution:

If they traveled 20% less on the second day, that means they traveled 80% of the distance they traveled the first day.

365 miles * .8 = 292.

You could also solve this as:
20% of 365 is 73 miles
365 * .2 = 73.
So they traveled 73 less miles on the second day.
365 miles on the first day - 73 miles less on the second day = 292 miles.

I hope this helps!
7 0
1 year ago
For several hours you watch a group playing dice on the street and you notice that the owner of the dice often wins. do you conc
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8 0
2 years ago
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A 3.00-g copper penny at 25.0°C drops from a height of50.0 m to the ground. (
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The potential energy, E, of the penny is given by E=mgh.  The energy, Q, required to raise the temperature of an object by an amount ΔT is given by Q=mcΔT.  We can equate these two to get the result but we must use proper units and include the 60%:
(0.6)mgh=mcΔT
We see we can divide out the mass from each side
0.6gh=cΔT,   then 0.6gh/c=ΔT
(0.6)9.81(m/s²)50m/385(J/kg°C) = 0.7644°C
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T=25.7644°C
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6 0
2 years ago
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