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Oxana [17]
2 years ago
13

What number must we multiply by $-\frac23$ to get a product of $\frac34$?

Mathematics
1 answer:
stich3 [128]2 years ago
7 0

Let x be unknown number. If number x is multiplied by -\dfrac{2}{3} and the product is equal to \dfrac{3}{4}, then

x\cdot \left(-\dfrac{2}{3}\right)=\dfrac{3}{4}.

To find x you should divide \dfrac{3}{4} by -\dfrac{2}{3}:

x=\dfrac{\dfrac{3}{4}}{-\dfrac{2}{3}}=\dfrac{3}{4}\cdot \left(-\dfrac{3}{2}\right)=-\dfrac{3\cdot 3}{4\cdot 2}=-\dfrac{9}{8}.

Answer: x=-\dfrac{9}{8}

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Mel slides down waterslide A, and Victor slides down waterslide B. After 2 seconds, Mel was 50 feet in the air, and after 5 seco
antiseptic1488 [7]
Mel moves 50-35=15 feet in 5-2=3 seconds. Descent rate=15/3=5 ft/sec.
Victor moves 60-50=10 feet in 4-1=3 seconds. Descent rate=10/3=3⅓ ft/sec. Mel is faster at 5 ft/sec.
7 0
2 years ago
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You bought $2000 worth of stocks in 2012. The value of the stocks has been decreasing by 10% each year. What will your stock be
goblinko [34]

Answer:

that is the solution to the question

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2 years ago
The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
What is the measurement of N?<br><br>A) 23° <br><br>B) 45° <br><br>C) 73° <br><br>D) 81°
alina1380 [7]

D) 81°

explanation:

90°-9° =81°

5 0
2 years ago
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The multiplication law is potentially helpful when we are interested in computing the probability of a. mutually exclusive event
Korvikt [17]

Answer:

b )  the intersection of two events

Step-by-step explanation:

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Probability of two events occurring that is called intersection of two events. There are two different set of events , called independent and dependent events.

Independent events  event is not affected by a previous event.

A dependent event is when one event influences the outcome of another event . To find the intersection of two events, whether they are independent or dependent, multiply the two probabilities together.

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