Answer:
c
Step-by-step explanation:
ANSWER
The correct option is,

EXPLANATION
We were given that the solutions of the quadratic equation are

and

This tells us that,

and

are factors of the quadratic equation.
This implies that the quadratic equation is of the form,

We were also told that

is a non zero constant.
This means that we can use k to multiply the whole equation and the solution will not be affected.
Our equation now becomes,

Hence the correct answer is A.
Answer:
If a box is supposed to contain 18 ounces, and the acceptable error is 1 ounce, then the acceptable range is:
18 oz - 1oz = 17oz to 18oz + 1oz = 19oz
Then the acceptable range is (17oz, 19oz)
if the weight is smaller than 17 oz, the box is not acceptable.
If the weight is bigger than 19 oz, the box is not acceptable.
Then the graph of the boxes that can not be sold as full boxes is:
<---16---------17-------18--------19-------20----------->
where 17oz and 19oz are not included, because are acceptable weigths.
Answer:
neither.
Step-by-step explanation:
Answer:
V(t) = 25000 * (0.815)^t
The depreciation from year 3 to year 4 was $2503.71
Step-by-step explanation:
We can model V(t) as an exponencial function:
V(t) = Vo * (1+r)^t
Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.
We have that Vo = 25000, r = -18.5% = -0.185, so:
V(t) = 25000 * (1-0.185)^t
V(t) = 25000 * (0.815)^t
In year 3, we have:
V(3) = 25000 * (0.815)^3 = 13533.58
In year 4, we have:
V(4) = 25000 * (0.815)^4 = 11029.87
The depreciation from year 3 to year 4 was:
V(3) - V(4) = 13533.58 - 11029.87 = $2503.71