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Oxana [17]
2 years ago
13

What number must we multiply by $-\frac23$ to get a product of $\frac34$?

Mathematics
1 answer:
stich3 [128]2 years ago
7 0

Let x be unknown number. If number x is multiplied by -\dfrac{2}{3} and the product is equal to \dfrac{3}{4}, then

x\cdot \left(-\dfrac{2}{3}\right)=\dfrac{3}{4}.

To find x you should divide \dfrac{3}{4} by -\dfrac{2}{3}:

x=\dfrac{\dfrac{3}{4}}{-\dfrac{2}{3}}=\dfrac{3}{4}\cdot \left(-\dfrac{3}{2}\right)=-\dfrac{3\cdot 3}{4\cdot 2}=-\dfrac{9}{8}.

Answer: x=-\dfrac{9}{8}

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Ana played 555 rounds of golf, and her lowest score was an 808080.
laiz [17]

Answer:

c

Step-by-step explanation:

7 0
2 years ago
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The solutions to a quadratic equation are x = 2 and x = 7. If k is a nonzero constant, which of the following must be equal to t
Serggg [28]
ANSWER


The correct option is,
k(x - 2)(x - 7) = 0

EXPLANATION

We were given that the solutions of the quadratic equation are
x = 2
and
x = 7.

This tells us that,

x - 2

and
x - 7

are factors of the quadratic equation.



This implies that the quadratic equation is of the form,

(x - 2)(x - 7) = 0

We were also told that

k


is a non zero constant.



This means that we can use k to multiply the whole equation and the solution will not be affected.


Our equation now becomes,

k(x - 2)(x - 7) = 0


Hence the correct answer is A.
5 0
2 years ago
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The weight of a box of cereal can vary by of an ounce and still be sold as a full box. Each box is supposed to contain 18 ounces
mezya [45]

Answer:

If a box is supposed to contain 18 ounces, and the acceptable error is 1 ounce, then the acceptable range is:

18 oz - 1oz = 17oz to 18oz + 1oz = 19oz

Then the acceptable range is (17oz, 19oz)

if the weight is smaller than 17 oz, the box is not acceptable.

If the weight is bigger than 19 oz, the box is not acceptable.

Then the graph of the boxes that can not be sold as full boxes is:

<---16---------17-------18--------19-------20----------->

where 17oz and 19oz are not included, because are acceptable weigths.

8 0
2 years ago
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Which ordered pair is a solution of the equation?
noname [10]

Answer:

neither.

Step-by-step explanation:

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A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function
vitfil [10]

Answer:

V(t) = 25000 * (0.815)^t

The depreciation from year 3 to year 4 was $2503.71

Step-by-step explanation:

We can model V(t) as an exponencial function:

V(t) = Vo * (1+r)^t

Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

V(4) = 25000 * (0.815)^4 = 11029.87

The depreciation from year 3 to year 4 was:

V(3) - V(4) = 13533.58 - 11029.87 = $2503.71

7 0
2 years ago
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