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aleksley [76]
2 years ago
13

Twenty-four 4-inch wide square posts are evenly spaced with 5 feet between adjacent posts to enclose a square field, as shown. W

hat is the outer perimeter, in feet, of the fence? Express your answer as a mixed number.
Mathematics
2 answers:
Nata [24]2 years ago
4 0

Answer:

492 0/10

Step-by-step explanation:

We have that the perimeter is 4 times the length of the side, now we know that this side "l" is given by:

l = 4 in * 24 + 23 * 5 ft

l = 96 in + 115 ft

Now, we pass the inches to pes, knowing that 1 foot equals 12 inches, so

96 in * 1 ft / 12 in = 8 ft

therefore replacing it remains:

l = 8 ft + 115 ft

l = 123 ft

now the perimeter:

p = 123 * 4

p = 492

to change to a mixed number:

4920/10 = 492 0/10

Nadusha1986 [10]2 years ago
4 0

Answer:

129 1/3

Step-by-step explanation:

According to Alcumus, "There are 20 square posts which are not on a corner, so there are $20/4=5$ square posts on each side, not including the corner posts. Including the corner posts, there are 7 posts on a side, which means that there are 6 five-foot gaps between posts. Altogether the length of a side is $7\left(\frac{1}{3}\right)+6(5)=32\frac{1}{3}$ feet. The perimeter of the square is four times the side length, so the perimeter is $4\cdot 32\frac{1}{3}=\boxed{129\frac{1}{3}}$ feet."

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All you would do is times 12 by .15 or 15% you get 1.8 then all you do is 12 minus 1.8 you get $10.20 that is the price of a discounted pizza 

I hope this helps


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2 years ago
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kykrilka [37]

Answer:

Family will save 3600 gallons of water by replacing the shower-heads.

Step-by-step explanation:

Number of family members in a family = 5

Each member of the family averages shower per day = 8 minutes

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Therefore, family will use 3600 gallons less water by replacing the water saving water heads.

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2 years ago
Workers have packed 1,400 glasses in 7 boxes. If they pack 3 more boxes, how many glasses will they have packed in all?
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The ruby- throated hummingbird has a wing beat of about 200 beats per second. About how many wings beats would a huming bird hav
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If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
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