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2 years ago

7

The bar graph shows the numbers of reserved campsites at a campground for one week. What percent of the reservations were for Fr

iday or Saturday? Write the percent as a mixed number in simplest form.

1 answer:

natta225 [31]2 years ago

8 0

Answer:

$66\frac{2}{3} \%$

Step-by-step explanation:

See the attached bar graph.

The bar graph shows the numbers of reserved campsites at a campground for one week.

So, on Friday and Saturday, the total number of reserved campsites will be (26 + 30) = 56.

Now, the total number of reserved campsites from Monday to Sunday is (5 + 3 + 4 + 7 + 26 + 30 + 9) = 84.

Therefore, the percent of the reservations on Friday and Saturday will be

$\frac{56}{84} \times 100\% = \frac{200}{3}\% = 66\frac{2}{3}\%$ . (Answer)

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Which of the following functions shown in the table below is not an exponential function?

kramer

Answer:

B. f(x)

D. h(x)

Step-by-step explanation:

An exponential function will have a common ratio.

We check and see if the consecutive terms has a common ratio.

For f(x),

$\frac{5}{2} \ne \frac{10}{5}$

This is not an exponential sequence.

For g(x), we have:

$\frac{2}{1} = \frac{4}{2} = \frac{8}{4} = 2$

For h(x),

$\frac{1.25}{1} \ne \frac{1.5}{1.25}$

This is not an exponential sequence

For k(x),

$\frac{16}{64} = \frac{4}{16} = \frac{1}{4} = \frac{0.25}{1}$

6 0

2 years ago

Paula and Kawai shared $312 in the ratio of 6:7. How much money<br> did each person get?

Maslowich

Answer:

Paula get $\$144$ and Kawai get $\$168$ .

Step-by-step explanation:

Given: Paula and Kawai shared $\$312$ in the ratio of $6:7$ .

To find: How much money did each person get?

Solution:

We have,

Paula and Kawai shared $\$312$ in the ratio of $6:7$ .

So, let Paula get $\$6x$ and Kawai get $\$7x$ .

As per the question,

$6x+7x=312$

$\implies13x=312$

$\implies x=\frac{312}{13} =24$

Therefore, Paula get $6\times 24=\$144$ , and Kawai get $7\times 24=\$168$ .

Hence, Paula get $\$144$ and Kawai get $\$168$ .

6 0

2 years ago

A single bacterium lands in your mouth and starts growing by a factor of 4 every hour. After how many hours will the number of b

Ierofanga [76]

Answer:

After 5 hours, the number of bacteria will be 1024

Step-by-step explanation:

1 times 4 = 4

4 times 4 = 16

16 times 4 = 64

64 times 4 = 256

256 times 4 = 1024

It will take around 5 hours to exceed 1000

8 0

1 year ago

Complete the table to find the pattern in the number of combinations.

Andreas93 [3]

Answers:

Row 0: 1

Row 1: 1 1

Row 2: 1 2 1

Row 3: 1 3 3 1

Row 4: 1 4 6 4 1

=========================================

Explanation:

This is known as Pascal's Triangle. Each value, other than the '1's, is found by adding the values directly above it. For instance, the '4' is the result of 1+3, and the 6 is a result of 3+3, and so on.

You can use the nCr combination formula to find the same values.

Alternatively you can expand out binomials of the form (x+y)^n, for integer values of n, and you'll find the coefficients of the terms match perfectly with Pascal's Triangle.

5 0

2 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

2 years ago