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2 years ago

Complete the table to find the pattern in the number of combinations.

Mathematics

1 answer:

Andreas93 [3]2 years ago

5 0

Answers:

Row 0: 1

Row 1: 1 1

Row 2: 1 2 1

Row 3: 1 3 3 1

Row 4: 1 4 6 4 1

=========================================

Explanation:

This is known as Pascal's Triangle. Each value, other than the '1's, is found by adding the values directly above it. For instance, the '4' is the result of 1+3, and the 6 is a result of 3+3, and so on.

You can use the nCr combination formula to find the same values.

Alternatively you can expand out binomials of the form (x+y)^n, for integer values of n, and you'll find the coefficients of the terms match perfectly with Pascal's Triangle.

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The production department has installed a new spray machine to paint automobile doors. As is common with most spray guns, unsigh

Nesterboy [21]

Answer:

The numbers of doors that will have no blemishes will be about 6065 doors

Step-by-step explanation:

Let the number of counts by the worker of each blemishes on the door be (X)

The distribution of blemishes followed the Poisson distribution with parameter $\lambda =0.5$ / door

The probability mass function on of a poisson distribution Is:

$P(X=x) = \dfrac{e^{- \lambda } \lambda ^x}{x!}$

$P(X=x) = \dfrac{e^{- \ 0.5 }( 0.5)^ x}{x!}$

The probability that no blemishes occur is :

$P(X=0) = \dfrac{e^{- \ 0.5 }( 0.5)^ 0}{0!}$

$P(X=0) = 0.60653$

P(X=0) = 0.6065

Assume the number of paints on the door by q = 10000

Hence; the number of doors that have no blemishes is = qp

=10,000(0.6065)

= 6065

3 0

2 years ago

in any given year a factory has a 10% probability of having a serious accident. about every how many years might the factory exp

Likurg_2 [28]

Years for one serious accident is 10 year

Given:

Probability of having a serious accident = 10% every year

P(serious accident) = 0.1

Number of years = n

Computation:

Years for one serious accident = 1 / Probability of having a serious accident

Years for one serious accident = 1 / P(serious accident)

Years for one serious accident = 1 / 0.1

Years for one serious accident = 10 year

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5 0

2 years ago

What are the solution(s) to the quadratic equation 40 − x2 = 0?

Anni [7]

X = 20
First, you move the 40 to the other side.
-2x=-40
Then, you divided -40 by -2.
x= -40/-2
x= 20
x is 20 because the negatives cancel out making it positive.

4 0

2 years ago

Read 2 more answers

What is not a pair of equivalent fractions for 5/8 and 1/2

n200080 [17]

Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.
5/6: 10/12 OR 15/18
15/30: 5/10 OR 1/2
45/60: 8/12 OR 4/6

Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number.

5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8.
2/5 and 1/2: 2/5 and 2.5/5
9/9 and 5/7: 9/9 and ~5.7/9

Rewrite each in simple form: Find greatest common factor and divide.

9/54: 1/6
20/40: 1/2
100/110: 10/11

Are these fractions equivalent?
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole.

In what situation can you use multiplication to find equivalent fractions?
I'm sorry but I do not understand this question.
Source(s):I hope I helped, seeing as I have graduated with a math degree.

7 0

2 years ago

Which equation combines with the given equation to form a system of equations with the solution x = 3 and y = 9? x + 2y = 21

max2010maxim [7]

Yes. x=3 and y =9 are the solutions.
Because if you change x=3 and y =9 ,you will have
3+2* 9 =21
3+18 =21
21 =21 (true)

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2 years ago

Read 2 more answers