Answer:
(P(t)) = P₀/(1 - P₀(kt)) was proved below.
Step-by-step explanation:
From the question, since β and δ are both proportional to P, we can deduce the following equation ;
dP/dt = k(M-P)P
dP/dt = (P^(2))(A-B)
If k = (A-B);
dP/dt = (P^(2))k
Thus, we obtain;
dP/(P^(2)) = k dt
((P(t), P₀)∫)dS/(S^(2)) = k∫dt
Thus; [(-1)/P(t)] + (1/P₀) = kt
Simplifying,
1/(P(t)) = (1/P₀) - kt
Multiply each term by (P(t)) to get ;
1 = (P(t))/P₀) - (P(t))(kt)
Multiply each term by (P₀) to give ;
P₀ = (P(t))[1 - P₀(kt)]
Divide both sides by (1-kt),
Thus; (P(t)) = P₀/(1 - P₀(kt))
Answer:
Let 'x' and 'y' be two different numbers.
Leila says that 75% of a number will always be greater than 50% of a number. The inequality that represents this statement is the following:
0.75x > 0.5y
Let x = 100 and y=200. We have that:
0.75(100) > 0.5(200)
75 > 100 ❌ INCORRECT ❌
Given that we found a case in which 75% of a number is not greater than 50% of a number, we can conclude that Leila's claim is incorrect.
Hey there!
Divide 200 by 25.
200/25= 8
She is running an average of 8 m/s. (that's how we represent meters per second)
I hope this helps!
~kaikers
P= a+b+c = 76
side a = 2b = 30
side b = b = 15
side c = 2b + 1 = 31
