Answer:
The 42 inches long fishing rod will fit in the box.
Step-by-step explanation:
The diagonal of a cuboidal box is the largest measurement inside the box.
Now, the dimensions of the box are 10 inches by 10 inches by 40 inches.
Therefore, the diagonal length of the box is 
inches which is greater than 42 inches.
Hence, the 42 inches long fishing rod will fit in the box. (Answer)
Answer:
p= 7 socks
Step-by-step explanation:
gift card:$25
socks:$4
p = 7
Answer:
Greatest number of flowers that can be used in a bouquet is 8.
Step-by-step explanation:
In this question greatest number of flowers used in a bouquet will be decided by the "Greatest Common Factor" of the numbers of the flowers given.
So, factors of 16 = 1×2×2×2×2
Factors of 8 = 1×2×2×2
Factors of 32 = 1×2×2×2×2×2
Common factors = 1×2×2×2
Greatest Common Factor of these numbers will be = 1×2×2×2 = 8.
Therefore, greatest number of flowers that could be in a bouquet is 8.
<h3><u>Question:</u></h3>
Denzel earned money after school. He put 1/2 of this month's earnings into savings. He took the rest to spend at the amusement park. He spent 1/5 of this amount on popcorn and 3/4 of it on rides. What fraction of his earnings did he take to the park but not spend on rides or popcorn.
<h3><u>Answer:</u></h3>
fraction of money not spend in amusement park
<h3><u>Solution:</u></h3>
Let "x" be the total earnings
He put 1/2 of this month's earnings into savings
He took the rest to spend at the amusement park
He spent 1/5 of this amount on popcorn and 3/4 of it on rides
<em><u>So the fraction of money not spend in amusement park is:</u></em>
⇒ Remaining amount - (Amount spend on popcorn + amount spend on rides)
Thus fraction of money not spend in amusement park
If the glasses were origanum 40, and were on sale for 26,we minus them from eachother to find out how much money was saved. So 40-26= 14, if $14 was saved we put 14 over the original price and times it buy 100 14/40x100= 35%
So 35% was saved. 100-35= 65. Therefore 65% of the original price was paid and 35% was saved.
