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FromTheMoon [43]
2 years ago
9

A loaded moving truck is traveling 30 mph faster than a freight train. in the time it takes the train to travel 135 miles, the t

ruck travels 225 miles. find the speed of the truck
Mathematics
1 answer:
Alina [70]2 years ago
4 0
Speed of truck= x
speed of train=x-30
A loaded moving truck is traveling 30 mph faster than a freight train. in the time it takes the train to travel 135 miles, the truck travels 225 miles. find the speed of the truck.

A loaded moving truck is traveling 30 mph faster than a freight train...
(x-30)=speed of train
the time it takes the train to travel 135 miles, the truck travels 225 miles...
135/(x-30)=225/x
the you multiply on both sides the x values and get...
 135x=225x-6750
then you subtract 225x on both sides...
-90x=-6750
then you divide -90 on both sides...
x=75
the speed of the truck is 75mph
i hope this helped give me a thanks and a 5 star rating if it helped! c:



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Sample Answer: Write the equation using slope and y-intercept in slope-intercept form, y = –275x + 3500. Then, substitute the x and y values of the point into the equation, 1850 = –275(6) + 3500. Simplify to see if both sides are equivalent. Yes, the instructor is correct because both sides are equivalent.



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1 year ago
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Why does multiplying a + bi by the complex conjugate a -bi eliminate I from the expression
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<u>EXPLANATION</u>

The reason is that

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(a+bi)(a-bi)

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This further gives us,

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Since the i^2=-1, we substite to get;

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2 years ago
the dot plot above identifies the number of pets living with each of 20 families in an apartment building .what fraction of fami
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B. ⅕

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Number of families with more than 2 pets = 3 + 1 = 4

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1 year ago
12. A cyclist travels 40 km at a speed of x km/h. Find the time
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Answer:

Step-by-step explanation:

distance = rate times time, so

           

           distance

time = --------------

               rate

Here the distance is 40 km and the rate is x.  Then

              40 km

time = --------------  =  (40/x) hr

             x km/hr

If the speed is reduced by 2 km/hr, we get:

              40 km                                            40 km                  40

time = -------------------------------  or time = ----------------------- = --------- hr

             (x km/hr - 2 km/hr)                      (x - 2) (km/hr)       x - 2

The difference between the times is:

 40          40

-------- - --------- = 1 hr          Solve this for the original speed, x

x - 2         x

40x - 40x + 80                                80

-----------------------  =  1 hr     or     ------------ = 1     or 80 = x^2 - 2x

     x(x - 2)                                     x(x - 2)

Rewriting this in standard quadratic form:  x^2 - 2x - 80 = 0

Here a = 1, b = -2 and c = -80, and so the discriminant b^2 - 4ac is:

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The solutions are:

   

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              2                      2

The original speed was 10 km/hr

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Answer:

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Now, you need to add that amount to the price of the lunch:

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According to this, the answer is that the total cost of the lunch including the tip is $15.21.

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