Solve the linear equation 2.25 – 11j – 7.75 + 1.5j = 0.5j – 1.
2 answers:
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Answer:
a) Total cost =
b) 11 days
Step-by-step explanation:
Given:
(a)
Number of days in hospital =
Cost of operation = $ 500
Cost of nursing per day = $170
∴ Cost of nursing for days = $
Therefore, the expression for total cost of her operation and nursing care is given as,
, where
is the total cost.
(b)
Given:
Total cost of operation =
Using the expression obtained in (a), we solve for .
Plug in 2370 for C and solve for . This gives,
Therefore, Angharad stayed in hospital for 11 days.
Answer:
0.67 mi
Step-by-step explanation:
The diagram illustrating the question is shown in the attach photo.
In triangle DCA,
Opposite = H
Adjacent = b
Angel θ = 27°
Tan θ = Opp /Adj
Tan 27° = H/b
Cross multiply
H = b x Tan 27°... (1)
From triangle DSA,
The diagram illustrating the question is shown in attach photo.
In triangle DCA,
Opposite = H
Adjacent = 2.3 – b
Angel θ = 34°
Tan θ = Opp /Adj
Tan 34° = H/ 2.3 – b
Cross multiply
H = Tan 34° (2.3 – b) .. (2)
Equating equation (1) and (2)
b x Tan 27° = Tan 34° (2.3 – b)
0.5095b = 0.6745(2.3 – b)
0.5095b = 1.55135 – 0.6745b
Collect like terms
0.5095b + 0.6745b = 1.55135
1.184b = 1.55135
Divide both side by 1.184
b = 1.55135/1.184
b = 1.31 mi
Substitute the value of b into any of the equation to obtain the height (H). In this case we shall use equation 1.
H = b x Tan 27°
H = 1.31 x Tan 27°
H = 0.67 mi
Therefore, the height of the drone is 0.67 mi
