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2 years ago

Would appreciate an explanation. PLEASE ANSWER THIS

Mathematics

1 answer:

Radda [10]2 years ago

8 0

c^2 = a^2 + b^2 - 2*ab*Cos(C)

c = 16; a = 17; b = 8 (what you call a and b don't really matter. c does). Substitute.

16^2 = 17^2 + 8^2 - 2*17*8*Cos(C) Add the first 2 on the right.

256 = 289 + 64 - 282*cos(C)

256 = 353 - 282*cos(C) Whatever you do, don't do any more combing on the right side. Subtract 353 from both sides.

-97 = -282 * cos(C ) Divide by 282

0.34397 = cos(C)

cos-1(0.34397) = C ; C = 69.88 degrees.

Do you need more help on this question? All of these are done the same way.

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3. Solve 2log4y - log4 (5y - 12) = 1/2<br>

Ilia_Sergeevich [38]

Answer:

y = 4 or y = 6

Step-by-step explanation:

2log4y - log4 (5y - 12) = 1/2

2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms

log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms

log_4(y^2/(5y-12)) = log_4(2) remove logarithm

y^2/(5y-12) = 2 cross multiply

y^2 = 10y-24 rearrange and factor

y^2 - 10y + 24 = 0

(y-4)(y-6) = 0

y= 4 or y=6

4 0

2 years ago

Which equation represents the line that passes through points (0, 6) and (2, 0)? A.)y = negative one-third x + 2 B.)y = negative

Rudiy27

Find the slope of the line through (x1,y1) = (0,6) and (x2,y2) = (2,0)

m = (y2 - y1)/(x2 - x1)

m = (0 - 6)/(2 - 0)

m = -6/2

m = -3

The slope is -3

Since we're given the point (0,6) to be on the line, we know the y intercept is b = 6.

Plug m = -3 and b = 6 into y = mx+b to get y = -3x+6

Answer: Choice D) y = -3x+6

5 0

2 years ago

Read 2 more answers

A circle with radius of \greenD{1\,\text{cm}}1cmstart color #1fab54, 1, start text, c, m, end text, end color #1fab54 sits insid

MatroZZZ [7]

Answer:

$8.86cm^2$

Step-by-step explanation:

Given the rectangle of 3cm by 4cm and a circle of 1 cm inside it:

The Area of the shaded portion =Area of Rectangle-Area of Circle

Area of a Rectangle=Length X Width $=3 X 4 =12cm^2$

Area of the circle = $\pi r^2=\pi X 1^1=3.142cm^2$

Area of the shaded portion=12-3.142

$=8.86cm^2$

6 0

2 years ago

The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − (x − π/2) + 1/6 (x − π/2)3 + R3(x). Usin

Otrada [13]

Answer:

The cosine of 86º is approximately 0.06976.

Step-by-step explanation:

The third degree Taylor polynomial for the cosine function centered at $a = \frac{\pi}{2}$ is:

$\cos x \approx -\left(x-\frac{\pi}{2} \right)+\frac{1}{6}\cdot \left(x-\frac{\pi}{2} \right)^{3}$

The value of 86º in radians is:

$86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi$

$86^{\circ} = \frac{43}{90}\pi\,rad$

Then, the cosine of 86º is:

$\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}$

$\cos 86^{\circ} \approx 0.06976$

The cosine of 86º is approximately 0.06976.

8 0

2 years ago

A large city in the ancient world was square-shaped. measured in miles, its area numerically exceeded its perimeter by about 132

melisa1 [442]

Area = perimeter + 132.

Let each side of the city be x miles long, then:-

x^2 = 4x + 132
x^2 - 4x - 132 = 0

x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2

x = 13.66, -9.66 We ignore the negative

So the city has dimension of 13.66 * 13.66

13.7 * 13.7 to nearest 10th

7 0

2 years ago