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Kay [80]
2 years ago
8

A student spends 17/35 of his pocket money on transport and fruits. He spends 5/6 of the remainder on sweets. What fraction of h

is pocket money does he spend on sweets?
Mathematics
1 answer:
Mashutka [201]2 years ago
6 0

Answer: 3/7 is the pocket money he spends on sweets

Step-by-step explanation:

Let the amount student spends be x

He spends 17/35x on transport and fruits

He spends 5/6 (x - 17/35x) on sweets

5/6 * (x -17/35x)

5/6 * 18/35x

= 3/7x

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mojhsa [17]
The answer would be one because  .9998 would round the 9 to a 10 which would round the second 9 and then the third nine to make 1

3 0
2 years ago
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The table shows some values of a function of the form y = ax2 + bx + c.
natali 33 [55]

Answer:

Value of constant term c is (-4)

Step-by-step explanation:

The given table represents a function which is in the form of a quadratic equation,

y = ax² + bx + c

We choose three points (3, -10), (4, -16) and (5, -24) from the table and satisfy the equation to get the values of a, b, and c.

For point (3, -10)

-10 = a(3)² + 3b + c

9a + 3b + c = -10 -------(1)

For point (4, -16)

-16 = a(4)² + 4b + c

16a + 4b + c = -16 ------(2)

For point (5, -24)

-24 = a(5)² + 5b + c

25a + 5b + c = -24 -----(3)

Equation (1) - equation (2)

(9a + 3b + c) - (16a + 4b + c) = -10 + 16

-7a - b = 6

7a + b = -6 ------(4)

Equation (2) - equation (3)

(16a + 4b + c) - (25a + 5b + c) = -16 + 24

-9a - b = 8

9a + b = -8 -------(5)

Equation (4) - Equation (5)

(7a + b) - (9a + b) = -6 + 8

-2a = 2

a = -1

From equation (4),

-7(1) + b = -6

b = -6 + 7

b = 1

From equation (1)

9(-1) + 3(1) + c = -10

-9 + 3 + c = -10

c = -10 + 6

c = -4

Therefore, the value of constant term c is (-4).

5 0
2 years ago
A welder drops a piece of red-hot steel on the floor. The initial temperature of the steel is 2,500 degrees Fahrenheit. The ambi
sergey [27]

Answer: After 18.05 minutes, the temperature of steel becomes 100 degrees.

Step-by-step explanation:

Since we have given that

Initial temperature = 2500

At t = 0,

we get that

f(t)=Ce^{-kt}+80\\\\2500=C+80\\\\2500-80=C\\\\2420=C

After 2 minutes, the temperature of the steel is 1500 degrees.

so, it becomes,

1500=2420e^{-2k}+80\\\\1500-80=2420e^{-2k}\\\\\dfrac{1420}{2420}=e^{-2k}\\\\0.587=e^{-2k}\\\\\ln 0.587=-2k\\\\-0.533=-2k\\\\k=\dfrac{0.533}{2}\\\\k=0.266

So, We need to find the number of minutes when the temperature of steel would be 100 degrees.

So, it becomes,

100=2420e^{-0.266t}+80\\\\100-80=2420e^{-0.266t}\\\\20=2420e^{-0.266t}\\\\\dfrac{20}{2420}=e^{-0.266t}\\\\\ln \dfrac{20}{2420}=-0.266t\\\\-4.8=-0.266t\\\\t=\dfrac{4.8}{0.266}\\\\t=18.05

Hence, after 18.05 minutes, the temperature of steel becomes 100 degrees.

7 0
2 years ago
In regional spelling bee, the 8 finalists consist of 3 boys and 5 girls. Find the number of sample point the sample space S for
Minchanka [31]

Answer:

i) There are 40320 possible orders

ii) There are 336 possible orders for the first 3 positions.

Step-by-step explanation:

Given: The number of finalists = 8

The number of boys = 3

The number of girls = 5

To find the number of sample point the sample space S for the number of possible orders, we need to find factorial of 8!

The number of possible orders = 8!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

= 40320

ii) From all 8 finalist, we need to choose first 3 position. Here the order is important. So we use permutation.

nPr =\frac{n!}{(n - r)!}

Here n = 8 and r = 3

Plug in n =8 and r = 3 in the above formula, we get

8P3 = \frac{8!}{(8 - 3)!}

= \frac{8!}{5!} \\= \frac{1.2.3.4.5.6.7.8}{1.2.3.4.5}

= 6.7.8

= 336

So there are 336 possible orders for the first 3 positions.

3 0
2 years ago
Athletes in a particular sport are classified as either offense or defense. The distribution of weights for the athletes classif
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Answer:

E. Bimodal.

Step-by-step explanation:

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2 years ago
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