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k0ka [10]
2 years ago
5

It takes 15 seconds for danial to play a card game. if the probability of winning the game is 0.1 and he has two minutes before

the class to play the game, what is the probability that he finally has a win right before class starts?
Mathematics
1 answer:
ycow [4]2 years ago
4 0
If Daniel has two minutes and each game lasts for 15 seconds then he has eight tries to win.  ( 120 seconds divided by 15 seconds = 8) And if his odds are .1 that means he has a 10% chance each game.  10% x 8 tries = 80% chance.  or .8
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Tyler wants to use $300 he has saved to buy a new guitar and join a music club. The guitar costs $140. The music club has a $25
ozzi

Answer:

ok __?__ is 11 and ___ is 3.55

Step-by-step explanation:

so first you subtract the 140 and 25 from the 300 then divide by 11.95, which gives you 11, then you multiply 11 times 11.95 and subtract that answer from 135.

4 0
1 year ago
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WILL GIVE 5 STARS TO THE PERSON WHO HELPS WITH AN EXPLANATION!!! If the 32 ounce bottle is 20% more than the typical bottle, how
Aleks04 [339]
So if 32 oz is 20% more than the average bottle, you multiply 32 by .20 which gives you 6.4. This means that the 32 oz bottle is 6.4 oz more than the regular bottle. Furthermore, 32 - 6.4 = 25.6 so that's how big the typical bottle is.
3 0
1 year ago
Which polynomial correctly combines the like terms and expresses the given polynomial in standard form?
dimaraw [331]

Answer:

D) n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3

Step-by-step explanation:

The given polynomial is 8mn^5  -2m^6 +5m^2 n^4 - m^3 n^3 + n^6 - 4m^6 + 9m^2n^4 -mn^5 - 4m^3n^3

Now we have to identify the like terms and simplify.

Like terms are nothing but the terms which have the same variables with same powers.

= (8mn^5 - mn^5) -2m^6 - 4m^6 + 5m^2 n^4 + 9m^2 n^4 - m^3n^3 - 4m^3n^3 +n^6

Now combine the like terms

= 7mn^5 - 6m^6 +14m^2 n^4-5m^3n^3 + n^6

It can be written in standard form

= n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3

The answer is D)

Hope this will helpful.

Thank you.

6 0
2 years ago
Read 2 more answers
An experiment was performed to compare the wear of two different laminated materials. Twelve pieces of material 1 were tested by
GenaCL600 [577]

Answer:

At 0.05 level of significance, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Step-by-step explanation:

We hypothesize that mean difference between abrasive wear of material 1 and material 2 is greater than 2.

So we write the null hypothesis H_0 : \mu_1 - \mu_2 >2,

and the alternative hypothesis H_1: \mu_1 - \mu_2 \leq 2.

We will find the T-score as well as the p-value. If the p-value is less than the level of significance, we will reject the null hypothesis, i.e. we will conclude that the abrasive wear of material 1 is less than that of material 2. Otherwise, we will accept the null hypothesis.

Since the variance is unknown and assumed to be equal, we will use the pooled variance

s_p^2 = \frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2} = 20.05,

where n_1 = 12, n_2 =10, s_1 =4, s_2 = 5.

The mean of material 1 and material 2 are \mu_1 =85, \mu_2=81 respectively and mean difference d is equal to 4. The hypothesize difference d_0 is equal to 2.

To find the T-score, we use the following formula

T = \frac{d - d_0}{\sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2} }}

Substituting all the values into the T-score formula gives us T = 1.04, and the respective p-value is equal to 0.31. This means we have enough statistical evidence not to reject the null hypothesis, and at 5% significance level, the abrasive wear of material 1 exceeds that of material 2 by more than 2 units.

6 0
1 year ago
Isabella can afford a $410-per-month car payment, and she's interested in either a sedan, which costs $21,600, or a station wago
mylen [45]

Answer:

isabella can afford neither the sedan nor the station wagon

Step-by-step explanation:

you read it and stop being a lazy

5 0
1 year ago
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