All categories

2 years ago

How many solutions does the equation 1/5(20x-25)=4x-5 have?

Mathematics

2 answers:

MariettaO [177]2 years ago

5 0

Answer:

Infinitely many solutions

Step-by-step explanation:

we need to simplify the equations

1/5(20x-25)=4x-5

distribute the 1/5

4x-5=4x-5

+5 to each side

4x=4x

divide each side by 4

x=x

since x=x there are infinitely many solutions.

meriva2 years ago

5 0

Answer:

no real solutions

Step-by-step explanation:

1/5(20x-25)=4x-5

1/5(20-25)=4-5

1/5(-5)=1

-1=1

You might be interested in

Water is poured into a conical paper cup at the rate of 3/2 in3/sec (similar to Example 4 in Section 3.7). If the cup is 6 inche

aliya0001 [1]

Answer:

The water level rising when the water is 4 inches deep is $\frac{3}{8\times \pi} inch/s$ .

Step-by-step explanation:

Rate of water pouring out in the cone = R= $\frac{3}{2} inch^3/s$

Height of the cup = h = 6 inches

Radius of the cup = r = 3 inches

$\frac{r}{h}=\frac{3 inch}{6 inch}=\frac{1}{2}$

r = h/2

Volume of the cone = $V=\frac{1}{3}\pi r^2h$

$V=\frac{1}{3}\pi r^2h$

$\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi r^2h)}{dt}$

$\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi (\frac{h}{2})^2h)}{dt}$

$\frac{dV}{dt}=\frac{1}{3\times 4}\pi \times \frac{d(h^3)}{dt}$

$\frac{dV}{dt}=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}$

$\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}$

h = 4 inches

$\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3\times (4inches )^2\times \frac{dh}{dt}$

$\frac{3}{2} inch^3/s=\pi\times 4\times \frac{dh}{dt} inches^2$

$\frac{dh}{dt}=\frac{3}{8\times \pi} inch/s$

The water level rising when the water is 4 inches deep is $\frac{3}{8\times \pi} inch/s$ .

6 0

2 years ago

If your front lawn is 17.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snowflakes every minu

Alexus [3.1K]

Answer: 42.84 kg

Step-by-step explanation: Lawn is 17 ft x 20 ft.

Its area is S = 17 x 20 = 340 ft²

Each ft² of lawn accumulates 1050 snowflakes/min, 1ft² = 1050 s.f./min.

As 1 hour has 60 min, the lawn accumulates 63000/hour →

1050 x 60 = 63000

1ft² = 63000s.f./hour

This way, 340 ft² of lawn will accumulate 21,420,000 s.f/hour →

340 x 63000 = 21420000

As 1 snowflake has 2mg, 21,420,000 will have 42,840,000 mg.

As 1kg = 1,000,000 mg

42,840,000/1,000,000 = 42.84 kg

3 0

2 years ago

The product of 18 and a number is 109.8

timama [110]

Answer:

6.1!

Step-by-step explanation:

The product means you multiply, so you should divide 109.8 by 18. That will get you 6.1 as the answer.

8 0

2 years ago

Read 2 more answers

Last Sunday, the average temperature was 8\%8%8, percent higher than the average temperature two Sundays ago. The average temper

SVETLANKA909090 [29]

Answer: The two answers are 1.08T and (1 + $\frac{8}{100}$ )T.

Step-by-step explanation:

Try multiplying 1.08 times any random number. If you use 5, 1.08 times 5 gives you 5.4. This makes sense. Solve the other other expression as well and substitute T with the SAME number that you used before (5). Hope that helps!

5 0

2 years ago

The fuel cost per hour for running a ship is approximately one half the cube of the speed (measured in knots) plus additional fi

andrezito [222]

Answer:

6 knots

Step-by-step explanation:

Let the speed be v knots

then time taken to cover 500 M = 500 / v hrs

fuel consumption /hr = 216 + 0.5v^3

let F be the fuel consumption for trip

= [500/v][216 + 0.5v^3]

= 500[216/v + 0.5v^2]

dF/dv = 500[ - 216/v^2 + v]

d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

or v = 216/v^2

or v^3 = 216

solving, we get v = [216]^(1/3) = 6 knots

7 0

2 years ago