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2 years ago

14

In the number 652.12, how does the value of the 2 in the hundredths place compare to the value of the 2 in the ones place?

1 answer:

Darina [25.2K]2 years ago

7 0

Answer:

1/100

Step-by-step explanation:

.02 is 2/100

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Un guardia forestal divisa, desde un punto de observación A, un incendio en la dirección N27° 10’ E. Otro guardia, que se encuen

Inga [223]

Answer:

la distancia del punto de observación A al incendio = 5.5 millas

la distancia del punto de observación B al incendio = 3.8 millas

Step-by-step explanation:

La expresión esquemática de la pregunta se puede ver en la imagen adjunta a continuación :

Del siguiente diagrama;

Usando la sine regla:

$\dfrac{sin \ F}{f} = \dfrac{sin \ A }{a}$

$\dfrac{sIn \ 79}{6} = \dfrac{sin \ 63}{a}$

a sin 79 = 6 sin 63

$a =\dfrac{6 \times sin \ 63}{sin \ 79}$

$a =\dfrac{6 \times 0.8910}{0.9816}$

a = 5.446 millas

la distancia del punto de observación A al incendio = 5.5 millas (a la décima más cercana)

$\dfrac{sin \ F}{f} = \dfrac{sin \ B}{b}$

$\dfrac{sin \ 79}{6} = \dfrac{sin \ 38}{b}$

b sin 79 = 6 sin 38

$b = \dfrac{6 \times sin \ 38}{sin \ 79}$

$b = \dfrac{6 \times0.6157 }{0.9816}$

b = 3.7635 millas

la distancia del punto de observación B al incendio = 3.8 millas (a la décima más cercana)

8 0

2 years ago

Exhibit 11-2 We are interested in determining whether the variances of the sales at two music stores (A and B) are equal. A samp

Fiesta28 [93]

Answer:

Option A , should not be rejected

Step-by-step explanation:

From the question we are told that:

Sample 1 $n=25$

Standard deviation 1 $\sigma_1=30$

Sample 2 $n=16$

Standard deviation 2 $\sigma_2=20$

Level of confidence $\alpha=95\%=>0.95$

Generally The Hypothesis are given as

$H_0:\sigma_1^2=\sigma_1^2$

$H_1:\sigma_1^2\neq \sigma_1^2$

Generally the equation for test Statistics is mathematically given by

$T=\frac{\sigma_1^2}{\sigma_2^2}$

$T=\frac{30^2}{20^2}$

$T=2.25$

Therefore

Critical Value

$X=(\alpha,df_1)$

$X'=(\alpha,df_2)$

Where

$df=n-1$

Therefore

$X=(0.95,24)$

$X'=(0.95,15)$

From Table

$T_{Critical}=T_x,T_{x'}$

$T_{Critical}=0.41,2.701$

Therefore

$T_x$

Hence,We fail to reject the Null Hypothesis $H_0$

Option A , should not be rejected

3 0

1 year ago

The quality control team of a company checked 800 digital cameras for defects. The team found that 20 cameras had lens defects,

dmitriy555 [2]

Answer:

0.025

Step-by-step explanation:

-This is a conditional probability problem.

-Let L denote lens defect and C charging defect.

#We first calculate the probability of a camera having a lens defect;

$P(lens)=\frac{Lens}{Total}\\\\=\frac{20}{800}\\\\=0.025$

#Calculate the probability of a camera having a charging defect:

$P(Charging)=\frac{Charging}{Total}\\\\=\frac{25}{800}\\\\=0.03125$

The the probability that a camera has a lens defect given that it has a charging defect is calculated as:

$P(L|C)=\frac{P(C)P(L)}{P(C)}\\\\=\frac{0.025\times 0.03125}{0.03125}\\\\=0.025$

Hence, the probability that a camera has a lens defect given that it has a charging defect is 0.025

6 0

2 years ago

THE NUMBER P IS 20 MORE THAN THE NUMBER Q.USING ALGEBRA WRITE THE RELATIONSHIP BETWEEN P AND Q

Anvisha [2.4K]

P=Q+20
or equivalently
P-Q=20

Edited 2018-03-18
Thank you Louli!

3 0

2 years ago

Read 2 more answers

A cistern can be completely drained by a pipe in 6 hours. It can be filled by two pipes in 4 hours and 5 hours, respectively. Ho

boyakko [2]

X/4 +x/5 -x/6=1
make the denominator the same:
15x/60 +12x/60 -10x/60=1
17x=60
x=60/17=3.53 hours

the second choice is the correct answer.

6 0

2 years ago