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jeyben [28]
2 years ago
14

The cost of filling up Jason's car is directly proportional to the number of gallons purchased. It if costs Jason $32.40 to purc

hase 15 gallons of gas, find the cost of purchasing 20 gallons of gas.
Mathematics
1 answer:
horsena [70]2 years ago
8 0

Answer:

$ 24.30

Step-by-step explanation:

1. $32.40 multiplied by 15 which would equal 486

2. Then you would do 486 divided by 20 which would equal $24.3

3. Then you just add the zero the the end

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Jack works for a company that pays him $20 an hour. His normal workday does not exceed 8 hours. After working 8 hours in a day,
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He would get $40 and the correct graphs is c
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Maria has 14 pencils, Ted has 9 pencils, Tom has 12 pencils, Lucinda has 13 pencils, and Jumana has 12 pencils. How can they red
Alisiya [41]

5 people.

14 + 9 + 12 + 13 + 12 = 60 total pencils.

60 pencils /  5 people = 12 pencils each.

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The rock band, Screamin’ Meanies, has a fan club that publishes a monthly newsletter. Expenses are $.35 for printing and mailing
Angelina_Jolie [31]
" break even " is when ur expenses = revenue.....there is no profit made when u break even

expenses : 0.35x + 770
revenue (ur income) : 0.55x

so they have to equal to break even...so set them equal to each other and solve for x
0.35x + 770 = 0.55x
770 = 0.55x - 0.35x
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770 / 0.2 = x
3850 = x <== they must sell 3850 copies to break even
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2 years ago
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A local fraternity is conducting a raffle where 55 tickets are to be sold—one per customer. There are three prizes to be awarded
harkovskaia [24]

Answer:

(a) 0.0152%

(b) 1.1663%

(c) 19.4297%

(d) 79.3787%

Step-by-step explanation:

Tickets bought by organizers = 4

Number of tickets = 55

Prizes = 3

(a) The probability that the four organizers win all of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{2}{53}\\P=0.0152\%

(b) The probability that the four organizers win exactly two of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{51}{53}+\frac{4}{55}*\frac{51}{54}*\frac{3}{53}+\frac{51}{55}*\frac{4}{54}*\frac{3}{53}\\P=1.1663\%

(c) The probability that the four organizers win exactly one of the prizes is:

P = \frac{4}{55}*\frac{51}{54}*\frac{50}{53}+\frac{51}{55}*\frac{4}{54}*\frac{50}{53}+\frac{51}{55}*\frac{50}{54}*\frac{4}{53}\\P=19.4397\%

(d) The probability that the four organizers win none of the prizes is:

P = \frac{51}{55}*\frac{50}{54}*\frac{49}{53}}\\P=79.3787\%

5 0
2 years ago
A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro
Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

5 0
2 years ago
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