Jane likes to exercise daily. The table shows the number of calories y she burns by exercising steadily for x minutes. How many
calories would she burn by exercising for 29 minutes?
2 answers:
Answer:
<h2>319 cal/min.</h2>Step-by-step explanation:
The table is attached.
You can observe in the table that there's no a value for 29 minutes.
That means we need to find the linear expression and then calculate the answer.
First, we need to find the ratio of change using two pairs of the given table and the following formula, (20,220) and (40,440) are the points
The ratio of change states that Jane burns 11 calories per minute. So, after 29 minutes, she will burn
You might be interested in
The rate of change of the risk of down syndrome (in percentage of births per year) is
r(x) = 0.004641x² - 0.3012x + 4.9, 20≤ x ≤ 45
where
x = maternal age at delivery.
The function giving risk as a percentage of births when maternal age is x is the integral of r(x). That is,
f(x) = 0.001547x³ - 0.1506x² +4.9x + c
When x = 30, f = 0.14%. Therefore
0.001547(30³) - 0.1506(30²) + 4.9(30) + c = 0.14
41.769 - 135.54 + 147 + c = 0.14
c = -53.089
Answer:
f(x) = 0.001547x³ - 0.1506x² + 4.9x - 53.089, 20 ≤ x ≤ 45
The function is graphed as shown below.
r(x) = 0.004641x² - 0.3012x + 4.9, 20≤ x ≤ 45
where
x = maternal age at delivery.
The function giving risk as a percentage of births when maternal age is x is the integral of r(x). That is,
f(x) = 0.001547x³ - 0.1506x² +4.9x + c
When x = 30, f = 0.14%. Therefore
0.001547(30³) - 0.1506(30²) + 4.9(30) + c = 0.14
41.769 - 135.54 + 147 + c = 0.14
c = -53.089
Answer:
f(x) = 0.001547x³ - 0.1506x² + 4.9x - 53.089, 20 ≤ x ≤ 45
The function is graphed as shown below.