Answer:
No. of gonjas = 52
No. of more nzemas than fantes = 78
Step-by-step explanation:
Total no. of people = 520
No. of fantes = × 520
No. of fantes = 156
No. of ewes = × 520 = 130
No. of nzemas = × 520 = 78
No. of gas = × 520 = 104
No. of gonjas = 520 - (156 + 130 + 78 + 104) = 52
No. of fantes = 156
No. of nzemas = 78
No. of more nzemas than fantes = 156 - 78 = 78
Pie chart of the following problem is shown below.
Answer: The correct option is (A) reduction.
Step-by-step explanation: Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.
As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:
AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.
And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:
We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.
Now, the scale factor is given by
Since the scale factor is less than 1, so the dilation will be a reduction.