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Leokris [45]
2 years ago
13

A house on the land measures 45 feet by 38 feet,a wooded area covers 118 feet by 60 feet,and the front yard is 78 feet by 40 fee

t.The remainder of the land
is farmed.How many acres of land are farmed?Round to the nearest tenth.Explain your answer.(Hint: 1 acre = 43,560 square feet)

Mathematics
1 answer:
den301095 [7]2 years ago
6 0
Rectanglearea=legnth timees width
triagnlearea=1/2base times height

ok so we find volume of entier land first

we can cut into triangle an rectangle

triangle=height=650-200=450
base=600
area=1/2*600*450=135000 ft^2

rectangle=200 times 600=120000

add
135000+120000=255000ft^2


find other areas and subtract
areahouse=45*38=1710
areawooded=118*60=7080
frontyard=78*40=3120
add
1710+7080+3120=11910

minus

255000-11910=243090

how many acres are farmed

43560ft^2=1acre
divide both sides by 43560
1ft^2=1/43560 acre

multiply both sides by 243090
243090ft^2=243090/43560acre=5.5805acre=5.6acre rounded

answer is 5.6 acer


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Liula [17]

https://jhmsmath.weebly.com/uploads/2/7/7/5/27756807/8th_grade_countdown.pdf go to this link page 52-54

6 0
2 years ago
The perimeter of a school crossing sign is 102 inches what is the length of each side
12345 [234]
Add up all sides lengths:

s+6  +    s+6    +  s  +    s    + 2s    = 102

solve for s:

6s + 12 = 102
6s = 90
s= 15


The lengths of sides are as follows:

15, 21, 21, 15, 30 inches



I hope that helps!



4 0
2 years ago
Read 2 more answers
What is the positive solution to this equation? 4x2 + 12x = 135​
Bas_tet [7]

Answer:

127/12

Step-by-step explanation:

4 × 2 + 12x = 135

(1. Simplify 4 x 2 to 8.

8 + 12x = 135

(2. Subtract 88 from both sides.

12x= 135 - 8

(3. Simplify 135 - 8 to 127

12x = 127

(4. Divide both sides by 12

x= 127/12

Decimal Form: 10.583333

I think this is the awnser, but don't quote me on that

4 0
2 years ago
g Steel used for water pipelines is often coated on the inside with cement mortar to prevent corrosion. In a study of the mortar
aleksandr82 [10.1K]

Answer:

P(X

And we can find this probability using the z table and we got:

P(z

Step-by-step explanation:

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

X \sim N(0.635,0.082)  

Where \mu=0.635 and \sigma=0.032

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the z table and we got:

P(z

7 0
2 years ago
A factory produces weighted balls to use for exercise, by filling spherical rubber shells of different sizes with a sand-like ma
kipiarov [429]

Answer: The radius of the ball must be 5.4 cm

Step-by-step explanation:

The information we have is:

Density of the material = 1.5 g/cm^3

Shell mass = 10 g

we want to find the radius of the ball, such when it is full, the mass is 1 kg.

The mass of the sphere is equal to the density of the material times the volume of the sphere.

The volume of the sphere is:

V = (4/3)*pi*r^3

where pi = 3.14 and r is the radius.

The mass of a filled ball is the mass of the filling material plus the mass of the shell, we have:

mass of the full ball = 1kg = 1000g =  (1.5g/cm^3)*((4/3)*pi*r^3) + 10g

1000g = (6.28g/cm^3)*r^3 + 10g

so we must find the value of r.

1000g - 10g = (6.28g/cm^3)*r^3

990g/(6.28g/cm^3) = r^3

157.64cm^3 = r^3

r = \sqrt[3]{157.64cm^3} = 5.4 cm

4 0
2 years ago
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