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Leokris [45]
2 years ago
13

A house on the land measures 45 feet by 38 feet,a wooded area covers 118 feet by 60 feet,and the front yard is 78 feet by 40 fee

t.The remainder of the land
is farmed.How many acres of land are farmed?Round to the nearest tenth.Explain your answer.(Hint: 1 acre = 43,560 square feet)

Mathematics
1 answer:
den301095 [7]2 years ago
6 0
Rectanglearea=legnth timees width
triagnlearea=1/2base times height

ok so we find volume of entier land first

we can cut into triangle an rectangle

triangle=height=650-200=450
base=600
area=1/2*600*450=135000 ft^2

rectangle=200 times 600=120000

add
135000+120000=255000ft^2


find other areas and subtract
areahouse=45*38=1710
areawooded=118*60=7080
frontyard=78*40=3120
add
1710+7080+3120=11910

minus

255000-11910=243090

how many acres are farmed

43560ft^2=1acre
divide both sides by 43560
1ft^2=1/43560 acre

multiply both sides by 243090
243090ft^2=243090/43560acre=5.5805acre=5.6acre rounded

answer is 5.6 acer


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Isoke is solving the quadratic equation by completing the square.10x2 + 40x – 13 = 0 10x2 + 40x = 13 A(x2 + 4x) = 13What is the
Elina [12.6K]

we have

10x^{2} + 40x - 13 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

10x^{2} + 40x =13

Factor the leading coefficient

10(x^{2} + 4x) =13 ----------> the value of A is 10

Complete the square. Remember to balance the equation by adding the same constants to each side

10(x^{2} + 4x+4) =13+40

10(x^{2} + 4x+4) =53

Rewrite as perfect squares

10(x+2)^{2} =53

10(x+2)^{2} =53  \\ (x+2)^{2} =\frac{53}{10} \\ \\ x+2=(+/-)\sqrt{\frac{53}{10}}  \\ \\ x1=-2+\sqrt{\frac{53}{10}}\\ \\ x2=-2-\sqrt{\frac{53}{10}}

therefore

the answer is

the value of A is 10

3 0
2 years ago
Read 2 more answers
2. During typhoon Ambo, PAGASA tracks the amount of accumulating rainfall. For the first three hours of typhoon, the rain fell a
zmey [24]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following information:

First three hours of typhoon: rate of Rainfall. = 25mm per hour

Typhoon slows down for an hour : then Rainfall began again at a constant rate of 20 mm per hour for the next 2 hours

Piecewise function which models Rainfall ad a function of time

Amount of Rainfall as a function of time = f(t)

f(t) = 25t ; if t≤ 3

When typhoon slowed down for an hour :

f(t) = 0;

f(t) = 25*3 ; for t ∈ (3, 4)

Then Rainfall at a constant rate of 20mm for another 2 hours

f(t) = (25 *3) + 20(t - 4) ; for t ∈ (5, 6)

5 0
2 years ago
A pair of socks costs $2.50 originally. The price is reduced to $1.75. What is the percent change?
telo118 [61]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

% change = difference / original x 100

% change = (0.75 / 2.5) x 100

% change = 30%

It was a 30% change

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6 0
2 years ago
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READ NOW for prize details: You really want to add smoked sausages to your menu and feel that you'll sell 12 units a night at $9
RideAnS [48]

Answer:

4.2 days

Step-by-step explanation:

8 0
2 years ago
Out of six computer chips, two are defective. If two chips are randomly chosen for testing (without replacement), compute the pr
Ratling [72]

Answer:

The probability that of the two chips selected both are defective is 0.1089.

Step-by-step explanation:

Let <em>X</em> = number of defective chips.

It is provided that there are 2 defective chips among 6 chips.

The probability of selecting a defective chip is:

P(X)=p=\frac{2}{6}=0.33

A sample of <em>n</em> = 2 chips are selected.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 2 and <em>p</em> = 0.33.

The probability function of a Binomial distribution is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...

Compute the probability that of the two chips selected both are defective as follows:

P(X=2)={2\choose 2}(0.33)^{2}(1-0.33)^{2-2}=1\times 0.1089\times 1=0.1089

Thus, the probability that of the two chips selected both are defective is 0.1089.

The sample space of selecting two chips is:

S = (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

     (2, 1),  (2, 3), (2, 4), (2, 5), (2, 6)

     (3, 1), (3, 2), (3, 4), (3, 5), (3, 6)

     (4, 1), (4, 2), (4, 3), (4, 5), (4, 6)

     (5, 1), (5, 2), (5, 3), (5, 4), (5, 6)

     (6, 1), (6, 2), (6, 3), (6, 4), (6, 5)

3 0
2 years ago
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