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kogti [31]
2 years ago
10

Sam purchased a new car for $17,930. The value of the car depreciated by 19% per year. When he trades the car in after x years,

the car is worth no more than $1,900. Fill in the values of a, b, and c to complete the exponential inequality of the form a(b)x ≤ c that can be used to determine the number of years after which the car is worth no more than $1,900. use a(b)^x,=c
Mathematics
1 answer:
In-s [12.5K]2 years ago
5 0
What you must do in this case is to use the potential type function given in the problem:
 a (b) ^ x = c
 We have:
 new car for $ 17,930
 a = 17930
 The value of the car depreciated by 19% per year
 b = 1-0.19 = 0.81
 the car is worth no more than $ 1,900
 c = 1900
 the exponential inequality is:
 a (b) ^ x ≤ c
 17930 (0.81) ^ x ≤ 1900
 Answer:
 the exponential inequality is:
 17930 (0.81) ^ x ≤ 1900
 where
 x: number of years
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Ester's choir wants to learn a new song for the school concert in 7 weeks. The song has 3,016 lines. The choir learns an equal n
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Answer:

the answer you will get is 61.5

Step-by-step explanation:

First you calcuate the number of days in the learning process there will be which there will be 49 days since 7 days x 7 weeks = 49 days. Then, you divide 3,016 and 49 to get 61.5510204 and then you round that up to get 61.5 or is you want a whole number with no decimals 62

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1 year ago
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A caterer makes 3 extra sandwhiches for every 20 sandwhiches a customer orders. What is the ratio of ordered sandwiches to extra
VMariaS [17]
You can solve this by making a proportion.

\frac{3}{20} =  \frac{x}{184}

you cross multiply and divide to solve this. your answer is 8.

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2 years ago
Imani is flying a drone. It takes off from a height of 24 feet above the ground and rises at a constant rate of 4.5 feet per sec
Firdavs [7]

Answer:

It will take 73 seconds.

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1 year ago
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A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first sta
Akimi4 [234]

Answer:

95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

Step-by-step explanation:

We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).

In the first stages of a clinical trial, it was successful for 7 out of the 14 women.

Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;

                             P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of women who find success with this new treatment = \frac{7}{14} = 0.50

          n = sample of women = 14

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the true proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                            level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u />

<u>95% confidence interval for p</u> = [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.50-1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } } , 0.50+1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } } ]

 = [0.238 , 0.762]

Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

4 0
2 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?
Basile [38]

Answer:

Step-by-step explanation:

The given quadratic equation is

2x^2+3x-8 = 0

To find the roots of the equation. We will apply the general formula for quadratic equations

x = -b ± √b^2 - 4ac]/2a

from the equation,

a = 2

b = 3

c = -8

It becomes

x = [- 3 ± √3^2 - 4(2 × -8)]/2×2

x = - 3 ± √9 - 4(- 16)]/2×2

x = [- 3 ± √9 + 64]/2×2

x = [- 3 ± √73]/4

x = [- 3 ± 8.544]/4

x = (-3 + 8.544) /4 or x = (-3 - 8.544) / 4

x = 5.544/4 or - 11.544/4

x = 1.386 or x = - 2.886

The positive solution is 1.39 rounded up to the nearest hundredth

8 0
2 years ago
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