All categories

2 years ago

10=ax-3b solve for x

2 answers:

8 0

10 = ax - 3b

First, add 3b to both sides. / Your problem should look like: 10 + 3b = ax.
Second, divide both sides by a. / Your problem should look like: $\frac{10 + 3b}{a}$ = x.
Third, switch sides. / Your problem should look like: x = $\frac{10 + 3b}{a}$ which is your answer.

svetlana [45]2 years ago

3 0

10 = ax - 3b
10 + 3b = ax

x = (10+3b)/a

You might be interested in

On average, the number of customers who had items to return for refunds or exchanges at a certain retail store's service desk is

spayn [35]

Answer:

The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.

Step-by-step explanation:

With the weekly average we can estimate the daily average for customers, assuming 7 days a week:

$M=756/7=108$

We can model this situation with a Poisson distribution, with parameter λ=108. But because the number of events is large, we use the normal aproximation:

$P(\lambda)\approx N(\lambda,\lambda)$

Then we can calculate the z value for x=100:

$z=\frac{x-\mu}{\sigma}=\frac{100-108}{\sqrt{108}}=\frac{-8}{10.4} =-0.77$

Now we calculate the probability of x>100 as:

$P(x>100)=P(z>-0.77)=0.78$

The probability that the service desk will have at least 100 customers with returns or exchanges on a randomly selected day is P=0.78.

5 0

2 years ago

A hose with a larger diameter working alone can fill a swimming pool in 9 hours. A hose with a smaller diameter working alone ca

Vilka [71]

- The rate of the hose with the large diameter is:

Answer: A). 1/9.

- What is the unknown in the problem?

Answer: C). the time it takes for the hoses working together to fill the pool

-What part of the job does the hose with the large diameter do?

Answer: B). x/9

4 0

2 years ago

Customers enter the waiting line to pay for food as they leave a cafeteria on a first-come, first-served basis. The arrival rate

Elan Coil [88]

Answer:

The answer is B) 0.57.

Step-by-step explanation:

In this problem we have to apply queueing theory.

It is a single server queueing problem.

The arrival rate is $\lambda=4$ and the service rate is $\mu=7$ .

The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:

$p=\frac{\lambda}{c\mu} =\frac{4}{1*7}=0.57$

where c is the number of server (in this case, one server).

3 0

2 years ago

You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In

alexandr1967 [171]

C. $360

$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)

4 0

2 years ago

Read 2 more answers

there are 6 grams of fat per serving of granola. each serving provides 180 calories. what percentage of these calories is from f

expeople1 [14]

There are 6 grams of fat per serving in granola. 
Each serving provides 180 calories. 
There are 9 calories of fat in each gram. 
The percentage of calories from fat in granola is? 

30%

7 0

2 years ago