All categories

2 years ago

10=ax-3b solve for x

2 answers:

8 0

10 = ax - 3b

First, add 3b to both sides. / Your problem should look like: 10 + 3b = ax.
Second, divide both sides by a. / Your problem should look like: $\frac{10 + 3b}{a}$ = x.
Third, switch sides. / Your problem should look like: x = $\frac{10 + 3b}{a}$ which is your answer.

svetlana [45]2 years ago

3 0

10 = ax - 3b
10 + 3b = ax

x = (10+3b)/a

You might be interested in

One week, Abigail earned $396.80 at her job when she worked for 16 hours. If she is paid the same hourly wage, how many hours wo

Delicious77 [7]

$396.80 divided by 16 to find the hourly wage you get $24.80 per hours so she works 1 hour to get that much so then in order to compute the amount of hours she’ll have to work you divide $148.80 by $24.80 to get 6. She has to work 6 hours to earn $148.80.

3 0

2 years ago

Yohanne and Mikaela completed a 1-km race. Yohanne finished the race 1 minute after Mikaela. If the speed of Mikaela is 50 meter

lilavasa [31]

Answer: 5 min

Step-by-step explanation:

Given

Length of the race track $l=1\ km\ or\ 1000\ m$

Suppose the speed of Yohanne is $v_y=x\ m/min.$

then Mikaela speed is $v_m=50+x$

the difference in the finishing time is 1 minute i.e.

$\Rightarrow \dfrac{1000}{x}-\dfrac{1000}{50+x}=1\\\\\Rightarrow \dfrac{50+x-x}{x(50+x)}=\dfrac{1}{1000}\\\\\Rightarrow \dfrac{50}{x(50+x)}=\dfrac{1}{1000}\\\\\Rightarrow x^2+50x-50,000=0\\\\\Rightarrow x^2+250x-200x-50,000=0\\\\\Rightarrow (x+250)(x-200)=0\\\\\Rightarrow x=200\ m/min.$

Time taken by Yohanne is

$\Rightarrow t=\frac{1000}{200}=5\ min$

7 0

1 year ago

Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2

kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

$\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}$

Multiply -y+x=2 by 2: -2y+2x=4

$\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}$

so adding

$-2y+2x=4$

$+$

$\underline{2y-2x=7}$

$0=11$

so the system of equations becomes

$\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}$

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0

2 years ago

The quadratic model f(x)=-5x^2 +200 represents the approximate height, in meters, of a ball x seconds after being dropped. The b

mel-nik [20]

Answer:

Third option: 5.48

Step-by-step explanation:

Given the quadratic model that represents the approximate height in meters of the ball $f(x)=-5x^2 +200$ . the time in seconds x, when the ball is 50 meters from the ground can be calculated by substituting $f(x)=50$ and solving for x.