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andreyandreev [35.5K]
1 year ago
7

The population of a village is modeled by the function P(t) = 890e0.024t, where P is the population after t years. What does 890

represent?
Mathematics
2 answers:
attashe74 [19]1 year ago
4 0

Answer:

Initial Value

Step-by-step explanation:

Trust

mars1129 [50]1 year ago
3 0

Answer:

I believe the answer is A. Population Growth Rate

Step-by-step explanation:

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The slope intercept form for this line would be in the form of y=mx+b. The slope is m and the y-intercept is b. 

y = (slope)x + (y-intercept)

y = 2x - 3

So, the answer is C.

Hope I could help! Have a good one!
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2 years ago
Which equation is the inverse of y = 16x2 + 1? y = plus-or-minus StartRoot StartFraction x Over 16 EndFraction minus 1 EndRoot y
kifflom [539]

Answer:

The inverse is ±sqrt((x-1))/ 4

Step-by-step explanation:

y = 16x^2 + 1

To find the inverse, exchange x and y

x = 16 y^2 +1

Then solve for y

Subtract 1

x-1 = 16 y^2

Divide by 16

(x-1)/16 = y^2

Take the square root of each side

±sqrt((x-1)/16) = sqrt(y^2)

±sqrt((x-1))/ sqrt(16) = y

±sqrt((x-1))/ 4 = y

The inverse is ±sqrt((x-1))/ 4

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1 year ago
Circle C is shown. Secants U W and Y W intersect at point W outside of the circle. Secant U W intersect the circle at point V an
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78 degrees mArc V X in the diagram
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1 year ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

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1 year ago
a rectangle on a coordinate plane is translated 5 units up and 3 units to the left. which rule describes the translation?
andre [41]
The correct answer is (x, y) → (x – 3, y + 5) 
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