Y intercept: 0,-15 or just -15
Slope: 9
Answer:
Therefore the y-intercept of the function is 4.
Step-by-step explanation:
Intercepts:
The line which intersect on x-axis and y-axis are called intercepts.
y-intercept: The line or function which intersect at y-axis. So when the line intersect at y-axis, X coordinate is zero.
So in the given Function Put x = 0 we will get the y-intercept
Put x =0
Therefore the y-intercept of the function is 4.
Answer: b is the correct option
Step-by-step explanation:
Tamara earns her living as a salary plus commission employee. This means that the total amount she earns is not fixed.
Her annual salary is $48,000. There are 12 months in a year. This means
that her her monthly salary is 48000/12 = $4000
she earns 4% commission on all sales she makes.
If Tamara wants to make a total of $6,000 this month, it means that she wants to make an extra $2000($6000-$4000) this month. She can only make this from commission based on sales
Let the sales be x
4% of x = 2000
4/100 × x = 2000
0.04x = 2000
x= 2000/0.04 = $50000
In the diagram where as the triangle RST is cognruent to triangle XYZ and ask to calculate the value of X. Base on my calculation and through step by step procedure and with the guidance of the theories and by the use of formulas, I came up with an answer of 35.
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
