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Tatiana [17]
2 years ago
8

Which of the following is a perfect square trinomial ?

Mathematics
2 answers:
Ivahew [28]2 years ago
4 0

For this case, we have that by definition, a perfect square trinomial, is a polynomial of three terms (also called trinomial) that results from squaring a binomial.

(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2\\(a-b) ^ 2 = a ^ 2-2ab + b ^ 2

We have:

4x ^ 2-20xy + 25y ^ 2\\(2x) ^ 2 = 4x ^ 2\\(5y) ^ 2 = 25y ^ 2

So:

2 * 5y * 2x = 20xy

So, 4x ^ 2-20xy + 25y ^ 2we can write it as:

(2x-5y) ^ 2

Answer:

Option A

Cerrena [4.2K]2 years ago
3 0

Answer:

The answer is A

Step-by-step explanation:

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Roy wants to make a path from one corner of his yard to the other as shown below. The path will be 4 feet wide. He wants to find
Nataly_w [17]

Answer:

He is incorrect. The path will have an area of (4)(40) = 160 ft². The yard has an area of 600 ft². The area of the lawn will be the difference of the yard and path, so it is 440 ft².

Step-by-step explanation:

1. Original area of yard

A = lw = 40 × 15 = 600 ft²

2. Area of path

The path is a parallelogram.

A = bh = 4 × 40 =160 ft²

3. Remaining area

Remaining area = original area - area of path = 600 - 160 = 440 ft².

3 0
2 years ago
Determine the area of squre ABCD with AB=3cm<br>​
Travka [436]

Answer:

Area: 9 cm^{2}

Step-by-step explanation:

Since all sides of a square have equal lengths, the area of the square is a^{2} (a = length of a side).

Since the length of the side of the square is given (is 3cm), the area of the square is (3cm)^{2} =  9cm^{2}

8 0
1 year ago
Read 2 more answers
why polar coordinates seem better suited for circular-type functions, while the rectangular coordinate system seems better suite
irina1246 [14]
Because "circular-type" functions can be more easily described by the periodic functions \sin and \cos, which are deeply involved in the behavior of "circular-type" functions. Also, using a polar coordinate plane allows you to draw graphs of equations that typically aren't functions.

For example, the unit circle requires two equations to be graphed to fully represent the circle in the rectangular coordinate plane.

x^2+y^2=1\implies y=\pm\sqrt{1-x^2}

On the other hand, in polar coordinates, substituting x=r\cos\theta and y=r\sin\theta reduces this to a constant function,

(r\cos\theta)^2+(r\sin\theta)^2=r^2(\cos^2\theta+\sin^2\theta)=r^2=1\implies r=1 (since by definition, r\ge0)
7 0
1 year ago
Two fifths of the square of the number j in algebraic exprission
Tomtit [17]
Two-fifths (\frac{2}{5}) of the square of the number j (j²)

 \frac{2}{5}j²
5 0
2 years ago
Read 2 more answers
To evaluate the effect of a treatment, a sample of n=8 is obtained from a population with a mean of μ=40 , and the treatment is
Westkost [7]

Answer:

Step-by-step explanation:

a)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{32}{8} } }

t=-2.5

df=8-1=7

critical, t ,values=+/-2.365

here test statistic lie in rejection region,that why null hypothesis fails  

so Yes, its significant.

b)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{72}{8} } }

t=-1.67

df=8-1=7

critical, t ,values=+/-2.365

c)

sample variability increases, therefore likelihood of rejecting the null hypothesis decreases.

5 0
1 year ago
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