I'm sorry I'm too lazy to read all of that. However, I did get the main point. The river was going at 3 mph. Since he wanted to travel 10 miles upstream and downstream, you would have to subtract 20 by 3. This would mean he was going at a speed of 17 mph.
Answer:
C. 50
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
The higher the margin of error, the wider an interval is.
As the sample size increases, the margin of error decreases. If we want a widest possible interval, we should select the smallest possible confidence interval.
So the correct answer is:
C. 50
The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive
So as x approaches infinity then y approaches infinity
as x approaches -infinity then y approaches infinity
The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.
Now we check the x intercepts of the first graph
x intercepts of first graph is -4 and 2
Plug in -4 for x in f(x) and check whether we get 0
Now plug in 2 for x and check
So -4 and 2 are the x intercepts that satisfies f(x)
Hence first option is the graph of
B/C = K/L because they are similar
Answer:
<u>The correct answer is that a student have to score 1.41 standard deviations above the mean to be publicly recognized.</u>
Step-by-step explanation:
For answering the question, we don't know the score mean of the National Financial Capability Challenge Exam and neither the population or number of students who take the exam. The only information provided is that the public recognition in this normal distribution is only for students that scores in the top 8%. In other words for students above 92% of the population.
With this information, we can go to a Z Score Table and check that for being on the top 8% (above the 92% of any population), your result must be 1.405 standard deviations above the mean.
<u>Rounding the answer to 2 decimal places, it's 1.41 standard deviations above the mean.</u>
