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Nataliya [291]
2 years ago
12

Points A(-2,3), B(-5,-4), and C(2,-1) form triangle ABC on a coordinate plane. What is the area of this triangle in square units

?

Mathematics
2 answers:
Veseljchak [2.6K]2 years ago
5 0

1. Draw an accurate picture of the triangle in the coordinate axes, as shown in the attached picture.<span>

<span>2. Circumscribe a rectangle about the triangle, as shown in the picture. The coordinates of the points M, N, T are easily identifiable as shown in the picture.</span>

<span>3. The area of the triangle ABC is  The area of the rectangle - Area 1- Area 2- Area 3.</span>

Area 1 = 1/2(3*7)=21/2
Area 2 = 1/2(4*4)=1/2*16=8
<span>Area 3 = 1/2( 3*7)=21/2</span>

<span>Area 1+Area 2+Area 3=21/2+21/2+8=21+8=29 (units squared)</span>

<span>Area rectangle=  7*7=49 (units squared)</span>


<span>Answer: Area of triangle is 20 units squared.</span></span>

Nastasia [14]2 years ago
4 0

Answer:

The answer is 20, im taking the quiz rn

Step-by-step explanation:

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I am an odd number I am less than 100 the sum of my digits is 12 I am a multiple of 15 what number am I
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The answer is 75.


Let's look at your problem shall we:


Odd number: It should end with the numbers 1,3,5,7, and 9.

The number is less than 100: It should be from the number 1-99

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1 year ago
Find b, given that a = 20, angle A = 30°, and angle B = 45° in triangle ABC
Kamila [148]
<span>The side b is opposite to the angle B, applying the law of the sines, we have:

</span>\frac{a}{sinA} = \frac{b}{sinB}
\frac{20}{sin30^0} = \frac{b}{sin45^0}
\frac{20}{ \frac{1}{2} } = \frac{b}{ \frac{ \sqrt{2} }{2} }
20* \frac{ \sqrt{2} }{2}  = b* \frac{1}{2}
\frac{20 \sqrt{2} }{2} = \frac{b}{2}
2*b =2*20 \sqrt{2}
2b = 40 \sqrt{2}
b =  \frac{40 \sqrt{2} }{2}
\boxed{b = 20 \sqrt{2} }
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