Answer:
<em>The maximum number of kilowatt-hours is 235</em>
Step-by-step explanation:
<u>Inequalities</u>
Robert's monthly utility budget is represented by the inequality:
0.1116x + 23.77 < 50
Where x is the number of kilowatts of electricity used.
We are required to find the maximum number of kilowatts-hours used without going over the monthly budget. Solve the above inequality:
0.1116x + 23.77 < 50
Subtracting 23.77:
0.1116x < 50 - 23.77
0.1116x < 26.23
Dividing by 0.1116:
x < 26.23/0.1116
x < 235
The maximum number of kilowatt-hours is 235
Left is plus right is negative -11-(-15)=4 so you know 4 to the left
The correct answer is Choice A.
If you plot the points on a graph, you will see that there is a slope of -1 and the y-intercept is (0, 3).
This matches the equation of y = -x + 3 in Choice A.
The sum of two numbers is zero.
x + y = 0
y = -x
<span>Twice the smaller number subtracted from 3 times the larger number is 10.
Let x represent the larger number and y represent the smaller number.
Twice the smaller number: 2y
3 times the larger number: 3x
</span>Twice the smaller number subtracted from 3 times the larger number is 10.
3x - 2y = 10
-2y = -3x + 10
y = 3/2 x - 5
The equations are:
y = -x
y = 3/2 x - 5
The answer is the first choice.
Answer:
= 99 Ω
= 2.3094 Ω
P(98<R<102) = 0.5696
Step-by-step explanation:
The mean resistance is the average of edge values of interval.
Hence,
The mean resistance,
= 99 Ω
To find the standard deviation of resistance, we need to find variance first.

Hence,
The standard deviation of resistance,
= 2.3094 Ω
To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.


From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696