Given
joe is responsible for reserving hotel rooms for a company trip. His company changes plans and increases how many people are goi
2 answers:
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Answer:
There is no sufficient evidence to support the claim that wedding cost is less than $30000.
Step-by-step explanation:
Values (x) ∑(Xi-X)^2
----------------------------------
29.1 0.1702
28.5 1.0252
28.8 0.5077
29.4 0.0127
29.8 0.0827
29.8 0.0827
30.1 0.3452
30.6 1.1827
----------------------------------------
236.1 3.4088
Mean = 236.1 / 8 = 29.51
Statement of the null hypothesis:
H0: u ≥ 30 the mean wedding cost is not less than $30,000
H1: u < 30 the mean wedding cost is less than $30,000
Test Statistic:
Test criteria:
SIgnificance level = 0.05
Degrees of freedom = df = n - 1 = 8 - 1 = 7
Reject null hypothesis (H0) if
Finding in the t distribution table α=0.05 with df=7, we have
= -1.9861 > -2.365
Result: Fail to reject null hypothesis
Conclusion: Do no reject the null hypothesis
u ≥ 30 the mean wedding cost is not less than $30,000
There is no sufficient evidence to support the claim that wedding cost is less than $30000.
Hope this helps!
Answer:
95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].
Step-by-step explanation:
We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).
In the first stages of a clinical trial, it was successful for 7 out of the 14 women.
Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;
P.Q. = ~ N(0,1)
where, = sample proportion of women who find success with this new treatment =
= 0.50
n = sample of women = 14
<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>
So, 95% confidence interval for the true proportion, p is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%
level of significance are -1.96 & 1.96}
P(-1.96 < < 1.96) = 0.95
P( <
<
) = 0.95
P( < p <
) = 0.95
<u />
<u>95% confidence interval for p</u> = [ ,
]
= [ ,
]
= [0.238 , 0.762]
Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].
Answer:
The length of the remaining piece of thread is
Step-by-step explanation:
Given:
A tailor cuts a piece of thread One-half of an inch long from a piece Nine-sixteenths of an inch long.
Now, to find the length of the remaining piece of thread.
Total thread =
Tailor cuts a piece of thread =
Now, to get the length of the remaining piece of thread by subtracting tailor cuts a piece of thread from the total thread:
Therefore, the length of the remaining piece of thread is
Answer:
a) The expected value is
b) The variance is
Step-by-step explanation:
We can assume that both marbles are withdrawn at the same time. We will define the probability as follows
#events of interest/total number of events.
We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is .
Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is . Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.
Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is . So, we define the following probabilities.
Probability of winning:
Probability of losing
Let X be the expected value of the amount you can win. Then,
E(X) = 1.10*probability of winning - 1 probability of losing =
Consider the expected value of the square of the amount you can win, Then
E(X^2) = (1.10^2)*probability of winning + probability of losing =
We will use the following formula
Thus
Var(X) =