(1/6) x + 2 = 10
Step-by-step explanation:
Step 1 :
Let x be the number of points scored by the team.
Given Joe has scored 2 points more than one sixth of the point scored bynthe team
Step 2:
Based on the above given information the equation which gives the points scored by Joe is as follows:
(1/6) x + 2
Given that Joe has scored 10 points, we have
(1/6)x + 2 = 10
Step 3:
When we solve the above equation for x , we get the total number of points scored by the team
Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Answer:
<em>96π units²</em>
Step-by-step explanation:
Find the diagram attached
Area of a sector is expressed as;
Area of a sector = θ/2π * πr²
Given
θ = 3π/4
r = 16
Substitute into the formula
area of the sector = (3π/4)/2π * π(16)²
area of the sector = 3π/8π * 256π
area of the sector = 3/8 * 256π
area of the sector = 3 * 32π
<em>area of the sector =96π units²</em>
C=90°, A=75°, b=AC=19, x=AB
Without a figure, we see AC is adjacent to angle A, so
cos A = AC/AB = b/x
x = b/cos A = 10 / cos 75° ≈ 38.637
Answer: 38.6
The answer is 10/36 or 27.77%
here’s the working out
