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SCORPION-xisa [38]
1 year ago
7

You are a school photographer taking individual and class pictures for 2 classes of 21 students each. On average, each individua

l picture takes 3 minutes and a class picture takes 10 minutes. About how long should it take you to take all of the pictures?
Mathematics
2 answers:
kramer1 year ago
3 0
146 minutes in total. One student =3 minutes. So then 42x3= 126. Class picture is 10x2=20. So then add both of them you get 146.
erik [133]1 year ago
3 0

Answer:

It will take 143 minutes to take the pictures

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A=<3,0,-1>, find a vector b such that comp(sub a) b=2.
Anna35 [415]
Compab=a.b/|a|
b=<0,1,−2√10>
a.b= 2√10
|a| = √10
a.b/|a|=2√10 / √10=2


5 0
1 year ago
A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0
1 year ago
What are the solutions of 8x2 = 6 + 22x? Check all of the boxes that apply.
Sholpan [36]
Transpose all the terms in the left hand side of the equation. The equation then becomes,
                         8x²  - 22x - 6 =0
Divide both sides of the equation by 2,
                        4x² - 11x - 3 = 0 

In this equation, A = 4, B = -11, and C = -3

With the variables identified, the quadratic equation can be used to identify the roots,
                         x = (-B +/- √B² - 4AC) / 2A
The values of x in the equation are,
                        <em> x = 3 and x = -1/4
</em>
<em />Thus, the one of the answer to this item is the third choice, x = 3. <em>
</em>
6 0
1 year ago
Read 2 more answers
Margie divided 24 by 3​
Levart [38]

Answer:

24 divided by 3 is 8

Step-by-step explanation:

3 goes into 24, 8 times

3 0
1 year ago
Read 2 more answers
AC CE and D is the midpoint of CE. IF CE 10x + 18, DE =7x -1, and BC = 9x - 2, find AB, AB =
Anastasy [175]

Answer:

<h3>      If you mean: AC=CE, the answer is:  AB = 24</h3>

Step-by-step explanation:

D is the midpoint of CE, then

CD = DE = 0.5CE = 0.5(10x+18) = 5x + 9

So:   5x + 9 = 7x - 1

            -9          -9

        5x  =  7x - 8

        -7x      -7x

       -2x  =  -8

      ÷(-2)       ÷(-2)        

          x  =  4

AC = CE = 10x + 18 = 40 + 18 = 58

BC = 9x - 2 = 36 - 2= 34

AB = AC - BC = 58 - 34 = 24

4 0
2 years ago
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