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STatiana [176]
2 years ago
13

The cruise boat can carry up to 45 passengers. the company wants to know the minimum number of passengers needed per cruise to c

over its costs.this number is called the break-even point.a formula for calculating the break-even point is:break-even point = (fixed costs) ÷ (income per passenger – costs per passenger)the company collects the following data:based on this data (attached), what is the minimum number of passengers needed per cruise, so that the cruise company can be sure it will make a profit?
Mathematics
2 answers:
AnnyKZ [126]2 years ago
8 0
Your question needs more details. What was the total amount of profits ($) the company had made? One you figure that out you take ($) divided by (#) that will get you amount per person. Then for part two of the question you need how much money is considered a profit them. Once you have that you can they amount they need divide that by cost of a ticket. Then that is your answer. Just plug in the numbers to solve
o-na [289]2 years ago
5 0
The cruise boat can carry up to 45 passengers.The company wants to know the minimum number of passengers needed per cruise to cover its costs.This number is called the break-even point.A formula for calculating the break-even point is:Break-even point = (fixed costs) ÷ (income per passenger – costs per passenger)The company collects the following data:
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Nevin made tables of values to approximate the solution to a system of equations. First he found that the x-value of the solutio
prisoha [69]

Answer:

The correct option is B.

Step-by-step explanation:

The given equation are

y=4x-3

y=-5x+9

On solving both the equation, we get

4x-3=-5x+9

4x+5x=9+3

9x=12

9x=\frac{12}{9}=\frac{4}{3}

Put this value in the given equation.

y=4(\frac{4}{3})-3

y=\frac{16}{3}-3

y=\frac{16-9}{3}

y=\frac{7}{3}

The solution of the given system of equation is

(\frac{4}{3},\frac{7}{3})=(1.333,2.333)\approx (1.3,2.3)

The best approximation of the exact solution is (1.3,2.3). Therefore the correct option is B.

7 0
2 years ago
Read 2 more answers
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
2 years ago
The random variable X is normally distributed with mean 82 and standard deviation 7.4. Find the value of q such that P(82 − q &l
mezya [45]
P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
q = 0.583 x 7.4 = 4.31
8 0
1 year ago
Kiesha’s quality-control manager told her she must have 97% of her clocks functioning properly. She found a report that said 6 o
Lena [83]

Answer:

Step-by-step explanation:

Kiesha will have more than 97% of the products working.

Kiesha’s experimental probability is 1/50

When the inventory is 4000 clocks, the prediction is that 3920 clocks will work.

4 0
2 years ago
Read 2 more answers
1600 dollars is placed in an account with an annual interest rate of 5.25%. How much will be in the account after 25 years, to t
Andru [333]

Step-by-step explanation:

Exponential Functions:

y=ab^x

y=ab

x

a=\text{starting value = }1600

a=starting value = 1600

r=\text{rate = }5.25\% = 0.0525

r=rate = 5.25%=0.0525

\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.0525=1.0525

b=1+r=1+0.0525=1.0525

\text{Write Exponential Function:}

Write Exponential Function:

y=1600(1.0525)^x

y=1600(1.0525)

x

Put it all together

\text{Plug in time for x:}

Plug in time for x:

y=1600(1.0525)^{25}

y=1600(1.0525)

25

y= 5750.0628984

y=5750.0628984

Evaluate

y\approx 5750.06

y≈5750.06

3 0
1 year ago
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