Question

Which shows one way to determine the facts of x3+4x2+5x+20 by grouping

Answer 1

Answer:

$x^{2}(x+4)+5(x+4)\\(x^{2} +5)(x+4).$

Step-by-step explanation:

In order to be able to determine the facts of $x^{3}+4x^{2} +5x +20$

you just have ti group and search for a term in common that could help you factorize into two separated terms, first, you try and factorize the first two terms:

$x^{3}+4x^{2} \\x^{2} (x+4)$

Remember always trying to take out the maximum exponential possible, in this case we were able to withdraw the $x^{2}$ and this helps us to factorize easier the second one since we already have a term that we want to have in common whic wuold be (x+4):

$5x+20\\5(x+4)$

Now we just put together the  $x^{2}$ and the 5, and we multiply it by our common factor:

$(x^{2} +5)(x+4).$

Answer 2

X^2(x+4) + 5(x + 4)

(x^2 + 5)(x + 4)