The weight of a sack of potatoes was more than 11 pounds. Shana wants to write an inequality for the weight of the sack of potat
2 answers:
Answer: The constant that Shana should use in the inequality is 11.
Step-by-step explanation: Given that the weight of a sack of potatoes was more than 11 pounds and she wants to write an inequality for the weight of the sack of potatoes.
We are to find the constant that she should use in the inequality.
Let x pounds represents the weight of the sack of potatoes.
Then, according to the given information, the inequality can be written as
Thus, the required constant that Shana should use in the inequality is 11.
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Answer:
.
Step-by-step explanation:
In quadrilateral QRST, Q(-1,0), R(5,0), S(3.5,-6), T(-2.5,-6).
In quadrilateral Q'R'S'T', Q'(-1,2), R'(1,2), S'(0.5,0), T'(-1.5,0).
Distance formula:
Using distance formula , we get
Now,
Therefore the scale factor is .
Question not correct, so i have attached the correct question.
Answer:
SE = 0.59
Step-by-step explanation:
The mean of the students height is;
x' = (53 + 52.5 + 54 + 51 + 50.5 + 49.5 + 48 + 53 + 52 + 50)/10
x' = 51.35
Now, deviation from the mean for each height;
53 - 51.35 = 1.65
52.5 - 51.35 = 1.15
54 - 51.35 = 2.65
51 - 51.35 = -0.35
50.5 - 51.35 = -0.85
49.5 - 51.35 = -1.85
48 - 51.35 = -3.35
53 - 51.35 = 1.65
52 - 51.35 = 0.65
50 - 51.35 = -1.35
Now, square of the deviations above;
1.65² = 2.7225
1.15² = 1.3225
2.65² = 7.0225
-0.35² = 0.1225
-0.85² = 0.7225
-1.85² = 3.4225
-3.35² = 11.2225
1.65² = 2.7225
0.65² = 0.4225
-1.35² = 1.8225
Sum of the squared deviations;
2.7225 + 1.3225 + 7.0225 + 0.1225 + 0.7225 + 3.4225 + 11.2225 + 2.7225 + 0.4225 + 1.8225 = 31.525
Let's divide the sum by the DF of n - 1 i.e 10 - 1 = 9.
Thus;
31.525/9 = 3.50278
Taking the square root of that gives us the standard deviation.
Thus;
s = √3.50278
s = 1.8716
Formula for standard error is;
SE = s/√n
SE = 1.8716/√10
SE = 0.59
