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2 years ago

13

Catherine is buying a new TV and is looking for the best loan to pay for her purchase. What loan should she choose? A. Loan with

the highest APR B. Loan with the highest APY C. Loan with the lowest APR D. Loan with the lowest APY

2 answers:

Paul [167]2 years ago

6 0

Answer:

Lowest apr is right tested it on apex

sertanlavr [38]2 years ago

5 0

Answer:

Loan with the lowest APR

Step-by-step explanation:

Whenever anyone takes a loan from some bank, lowest APR is the main aspect that he person keeps in mind. APR stands for Annual Percentage Rate. Its the interest amount that a person pays for using the loan amount or credit from the bank. Everyone wants to pay lowest APR. Hence, option C is the answer.

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For an investment of $26,245, a quarterly statement reports that the account balance is $26,292. The statement also reports that

Oduvanchick [21]

The statement reports the investment's value has gone up. That is inconsistent with a negative rate of return, which would mean the value has gone down.

No, the reported rate of return does not seem reasonable.

4 0

2 years ago

Read 2 more answers

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

<em>Point a:</em>

The Expected value or the mean value of X with set of possible values D, denoted by <em>E(X)</em> or <em>μ </em>is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by <em>E[h(X)]</em> is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

<em>Point b:</em>

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and <em>E(X)</em> = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

2 years ago

A dive ring on the bottom of the pool is 10 feet below the surface of the water. Sabine dives down and brings the ring back to t

MissTica

The surface of the water is 0 feet. So 10 feet down means it is 0 - 10, or -10 feet as its final position.

8 0

2 years ago

Read 2 more answers

Which graph represents y=3 sqrt x+2

ziro4ka [17]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$y=3\sqrt{x+2}$

Remember that the radicand must be greater than or equal to zero

so

$x+2\geq 0$

solve for x

subtract 2 both sides

$x\geq -2$

The domain is the interval [-2,∞)

All real number greater than or equal to -2

For x=-2

$y=3\sqrt{-2+2}=0$

so

The range is the interval [0,∞)

All real number greater than or equal to 0

Find the y-intercept

Remember that the y-intercept is the value of y when the value of x is equal to zero

For x=0

$y=3\sqrt{0+2}$

$y=3\sqrt{2}$

$y=4.243$

The y-intercept is the point (0,4.243)

therefore

The graph in the attached figure

7 0

2 years ago

Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist

Lera25 [3.4K]

Answer:

$Sum = -81$

Step-by-step explanation:

See the comment for complete question.

Given

$c = 36$ ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

$x^2 + ax + 36 = 0$

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

$x = -\alpha$ and $x = -\beta$

Using the above roots, the equation can be represented as:

$(x + \alpha)(x + \beta) = 0$

Open brackets

$x^2 + (\alpha + \beta)x + \alpha \beta = 0$

To compare the above equation to $x^2 + ax + 36 = 0$ , we have:

$a = \alpha + \beta$

$\alpha \beta = 36$

Where: $\alpha, \beta$ and $\alpha \ne \beta$

The values of $\alpha$ and $\beta$ that satisfy $\alpha \beta = 36$ are:

$\alpha = -1$ and $\beta = -36$

$\alpha = -2$ and $\beta = -18$

$\alpha = -3$ and $\beta = -12$

$\alpha = -4$ and $\beta = -9$

So, the possible values of a are:

$a = \alpha + \beta$

When $\alpha = -1$ and $\beta = -36$

$a = -1 - 36 = -37$

When $\alpha = -2$ and $\beta = -18$

$a = -2 - 18 = -20$

When $\alpha = -3$ and $\beta = -12$

$a = -3 - 12 = -15$

When $\alpha = -4$ and $\beta = -9$

$a = -4 - 9 = -13$

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

$Sum = -37 -20 -15 - 9$

$Sum = -81$

7 0

2 years ago