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ValentinkaMS [17]
2 years ago
14

a bricklayer needs to order 6300kg of building sand.one grain of this sand weighs 7x10^-5. how many grains of sand are there in

6300 kg?Answer in standard form please.
Mathematics
1 answer:
gavmur [86]2 years ago
5 0

Answer:

44.1 x 10^-2

Step-by-step explanation:

Since one grain

= 7 x 10^-5

6300kg = 7 x 10^-5 x 6300

Put 6300 in standard form

7 x 10^-5 x 6.3 x 10^3

Multiply the whole numbers and add the exponents

7 x 6.3 x 10^-5 + 3

44.1 x 10^-2

There are 44.1 x 10^-2 grains of sand in 6300kg

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Answer:

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Step-by-step explanation:

We need to apply distributive property for the product of two expressions each consisting of two terms, and also use the properties of products of radicals of the same root:

(\sqrt{12} +\sqrt{6} )(\sqrt{6} -\sqrt{10} )=\\=\sqrt{12*6} -\sqrt{12*10} +\sqrt{6*6} -\sqrt{6*10} =\\=\sqrt{72} -\sqrt{120} +\sqrt{36} -\sqrt{60}

and now, we extract as many factors we can from the roots to reduce them:

\sqrt{72} -\sqrt{120} +\sqrt{36} -\sqrt{60} =\\=6\,\sqrt{2} -2\,\sqrt{30} +6-2\,\sqrt{15}

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2 years ago
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Step-by-step explanation:

Han is multiplying10x^4 by 0.5^3 and gets 5x^7 is not a polynomial because 0.5 is not an integer. What is the error in han’s thinking explain

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A polynomial is a combination of coefficients and variables. It is made up of one or more monomial. Han says that it is not a polynomial because 0.5 is not an integer. The statement is false. After multiplication we get 5x⁷. It has a variable x and constant 5. Hence, its is a polynomial.

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See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se
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Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

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Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 6, p = 0.2

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

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This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if P(X \geq 5) < 0.05

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P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05

Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

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Answer:

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Step-by-step explanation:

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