Tree...........................dock
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boat
use Pythagorean Theorem to satisfy...a^2 + b^2 = c^2
200^2 + b^2 = 300^2
b^2 = 300^2 - 200^2
b^2 = 50000 (get square root of each)
b = 223.606 (rounded to the nearest tenth.... = 223.6
c^2 = a^2 + b^2 - 2*ab*Cos(C)
c = 16; a = 17; b = 8 (what you call a and b don't really matter. c does). Substitute.
16^2 = 17^2 + 8^2 - 2*17*8*Cos(C) Add the first 2 on the right.
256 = 289 + 64 - 282*cos(C)
256 = 353 - 282*cos(C)
Whatever you do, don't do any more combing on the right side. Subtract 353 from both sides.
-97 = -282 * cos(C )
Divide by 282
0.34397 = cos(C)
cos-1(0.34397) = C ; C = 69.88 degrees.
Do you need more help on this question? All of these are done the same way.
Answer: 8
Step-by-step explanation:
Given: Pedro cut a sheet of poster board into 10 equal parts.
let x be the total sheet.
then, one part of sheet= 
of the sheet
Now, His brother used some of the poster board and now 8/10 is left.
Therefore, if Pedro wants to make a sign from each remaining part of the poster board.
then, The number of signs he can make= 
Hence, Pedro can make 8 signs.
A) set x as the number of cameras
18x=9x+1800
9x=1800
x=200
b) i'm assuming it's increasing production from my answer in a, so the profit would be 18(250)-(9*250+1800)=4500-4050=450
<span>Using the kinematic equations:
(final velocity)^2 = (initial velocity)^2 - 2 * acceleration * distance
Assuming the acceleration/deceleration on the car is constant from a constant force on the brakes. Converting from mph to m/s using 0.447 (so 34 mph is 15.2 m/s)
(0)^2 = (15.2)^2 - 2 * acceleration * 29
acceleration = 4.0 m/s^2
Had the car been going 105.4 mph (47.1 m/s)
(0)^2 = (47.1)^2 - 2 * 4 * distance
distance = 277 meters</span>
