A fishing boat lies 200 m due south of a large tree on the shoreline and 300 m southwest of the dock. The shoreline runs East to
West. Enter a number in the box to correctly complete the statement. Round the answer to the nearest tenth. The distance along the shore from the tree to the dock is about m
2 answers:
Answer:
Distance between dock and tree is 223.6 m.
Step-by-step explanation:
As per question distance between dock and boat is 300 m and distance between boat and tree is 200 m.
Let the distance between dock and tree is x m.
Therefore by applying Pythagoras theorem in the triangle formed
x² = 200² + 300²
x = √(300² - 200²) = √(90000 - 40000) = √50000 = 100√5 = 100×2.23606
x = 223.6 m
Therefore answer is distance between tree and dock will be 223.6 m.
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Answer:
(1) Correct option (A).
(2) The probability that Aadi will get Tails is 0.40.
Step-by-step explanation:
The information provided is:
- Eric throws a biased coin 10 times. He gets 3 tails.
- Sue throw the same coin 50 times. She gets 20 tails.
The probability of tail in both cases is:
Here,
P (T|E) implies the probability of tail in case of Eric's experiment.
P (T|S) implies the probability of tail in case of Sue's experiment.
(1)
Now, it is given that Aadi is going to throw the coin once.
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
In this case we need to compute the probability of Aadi getting Tails in a single toss.
As Sue uses a larger number of trials in the experiment, i.e. n = 50 > 30 times, according to the Central limit theorem, Sue's estimate is best because she throws it .
Thus, the correct option is (A).
(2)
As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:
Thus, the probability that Aadi will get Tails is 0.40.